반응형 일반화학/[15장] 화학 평형157 3.0 L 2.4 mol Cl2 1.0 mol NOCl 4.5×10^(-3) mol NO K 3.0 L 2.4 mol Cl2 1.0 mol NOCl 4.5×10^(-3) mol NO K At a particular temperature, a 3.0 L flask contains 2.4 mol of Cl2, 1.0 mol of NOCl, and 4.5×10^(-3) mol of NO. Calculate K at this temperature for the following reaction: 2NOCl(g) ⇌ 2NO(g) + Cl2(g) At a particular temperature, a 3.0 L flask contains 2.4 mol of chlorine, Cl2(g); 1.0 mol of nitrosyl chloride, NOCl(g); and 4.5×10^(-3) mol of nitr.. 2022. 11. 13. 이론적 평형상수. ([HA]/[A^-]) × ([B^-]/[HB])의 값 이론적 평형상수. ([HA]/[A^-]) × ([B^-]/[HB])의 값 는 약산 HA, HB의 이온화 반응식과 Ka이다. HA, HB의 pH가 같을 때, ([HA]/[A^-]) × ([B^-]/[HB])의 값은? > HA + H2O ⇌ A^- + H3O^+ ... Ka = 3×10^(-4) > HB + H2O ⇌ B^- + H3O^+ ... Ka = 8×10^(-5) --------------------------------------------------- ▶ 참고: 평형상수의 이론적 계산 [ https://ywpop.tistory.com/4154 ] --------------------------------------------------- HA, HB의 pH가 같다 = HA, HB의 [H3O^+].. 2022. 11. 10. H2(g) + I2(g) ⇌ 2HI(g) Kc 56 435℃ 0.045 mol H2 I2 10.0 L H2(g) + I2(g) ⇌ 2HI(g) Kc 56 435℃ 0.045 mol H2 I2 10.0 L The reaction of hydrogen and iodine to give hydrogen iodide has an equilibrium constant, Kc, of 56 at 435°C. a) What is the value of Kp? b) Suppose you mix 0.045 mol of H2 and 0.045 mol of I2 in a 10.0 L flask at 425°C. What is the total pressure of the mixture before and after equilibrium is achieved? c) What is the partial pressure of ea.. 2022. 11. 7. Kc 730℃ 2.18×10^6 H2(g) + Br2(g) ⇌ 2HBr(g) 12.0 L HBr 3.20 mol Kc 730℃ 2.18×10^6 H2(g) + Br2(g) ⇌ 2HBr(g) 12.0 L HBr 3.20 mol The equilibrium constant Kc for the reaction H2(g) + Br2(g) ⇌ 2HBr(g) is 2.18×10^6 at 730°C. Starting with 3.20 moles of HBr in a 12.0 L reaction vessel, calculate the concentrations of H2, Br2, and HBr at equilibrium. --------------------------------------------------- 반응 전 HBr의 몰농도를 계산하면, [HBr] = 3.20 mol / 12.0 L = 0.267 M ICE 도표를.. 2022. 11. 3. 2NOBr(g) ⇌ 2NO(g) + Br2(g) 25℃ 34% 0.25 atm Kp Kc 2NOBr(g) ⇌ 2NO(g) + Br2(g) 25℃ 34% 0.25 atm Kp Kc Consider the following equilibrium. 2NOBr(g) ⇌ 2NO(g) + Br2(g) If nitrosyl bromide (NOBr) is 34% dissociated at 25°C and the total pressure is 0.25 atm, calculate Kp and Kc for the dissociation at this temperature. --------------------------------------------------- 2NOBr(g) ⇌ 2NO(g) + Br2(g) 또는 NOBr(g) ⇌ NO(g) + 1/2 Br2(g) NOBr의 초기 압력 = p 라 가정하면.. 2022. 11. 3. 평형상수 Kc. [Br2] = 0.124 M, [Cl2] = 0.237 M, [BrCl] = 0.450 M 평형상수 Kc. [Br2] = 0.124 M, [Cl2] = 0.237 M, [BrCl] = 0.450 M 25℃에서 CCl4 내의 Br2와 Cl2 혼합물은 다음과 같이 반응한다. Br2 + Cl2 ⇌ 2BrCl 평형에서 [Br2] = 0.124 M, [Cl2] = 0.237 M, [BrCl] = 0.450 M일 때, 이 반응의 Kc는? --------------------------------------------------- ▶ 참고: 평형 상수 식 [ https://ywpop.tistory.com/7136 ] --------------------------------------------------- Br2 + Cl2 ⇌ 2BrCl 반응의 평형 상수 식 Kc = [BrCl]^2 / [Br2] [Cl.. 2022. 11. 2. 르 샤틀리에. F2 + Cl2 ⇌ 2ClF + 열 반응에서 Cl2 양 르 샤틀리에. F2 + Cl2 ⇌ 2ClF + 열 반응에서 Cl2 양 반응 F2 + Cl2 ⇌ 2ClF + 열 에서 Cl2의 양은 다음에 의해 어떻게 영향을 받을까? a) F2 첨가 b) ClF 첨가 c) 부피 감소 d) 온도 증가 e) 촉매 첨가 --------------------------------------------------- ▶ 참고: 르 샤틀리에 원리 [ https://ywpop.tistory.com/2685 ] --------------------------------------------------- a) F2 첨가 > 반응물 첨가. ---> 정반응 진행. ---> Cl2의 양은 감소. b) ClF 첨가 > 생성물 첨가. ---> 역반응 진행. ---> Cl2의 양은 증가. c) 부피.. 2022. 11. 2. 2NOBr(g) ⇌ 2NO(g) + Br2(g) density 4.495 g/L 4.086 g/L 2NOBr(g) ⇌ 2NO(g) + Br2(g) density 4.495 g/L 4.086 g/L A sample of gaseous nitrosyl bromide, NOBr, was placed in a container fitted with a frictionless, massless piston, where it decomposed to form nitrogen monoxide and bromine. 2NOBr(g) ⇌ 2NO(g) + Br2(g) The initial density of the system was recorded to be 4.495 g/L. After equilibrium was reached, the density was noted to be 4.086 g/L. Determin.. 2022. 10. 22. 르 샤틀리에 원리. CO(g) + 2H2(g) ⇌ CH3OH(g) 르 샤틀리에 원리. CO(g) + 2H2(g) ⇌ CH3OH(g) 메탄올은 Cu/ZnO/Al2O3 촉매 조건하에서 일산화탄소와 수소를 반응시켜 제조된다. CO(g) + 2H2(g) ⇌ CH3OH(g) ... ΔH° = –91 kJ 메탄올의 양이 증가되는 조건은? a) 온도 감소 b) 압력 증가 c) 헬륨 첨가 d) CO 첨가 e) 촉매 제거 --------------------------------------------------- ▶ 참고: 르 샤틀리에의 원리 [ https://ywpop.tistory.com/2685 ] --------------------------------------------------- CO(g) + 2H2(g) ⇌ CH3OH(g) ... ΔH° = –91 kJ CO(g) +.. 2022. 10. 22. 800. K 50. L 3.00 mol CO 2.00 mol Cl2 9.00 mol COCl2 Kc 800. K 50. L 3.00 mol CO 2.00 mol Cl2 9.00 mol COCl2 Kc An equilibrium mixture contains 3.00 mol CO, 2.00 mol Cl2, and 9.00 mol COCl2 in a 50. L reaction flask at 800. K. Calculate the value of the equilibrium constant, Kc, for the reaction CO(g) + Cl2(g) ⇌ COCl2(g) at this temperature. --------------------------------------------------- ▶ 참고: 평형상수 식 [ https://ywpop.tistory.com/7136 ] ----------.. 2022. 10. 14. 이전 1 2 3 4 5 6 7 8 ··· 16 다음 반응형
