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일반화학/[03장] 화학량론769

NaCl Na2SO4 NaNO3 mass Na 32.08% O 36.01% Cl 19.51% NaCl Na2SO4 NaNO3 mass Na 32.08% O 36.01% Cl 19.51% A sample containing NaCl, Na2SO4, and NaNO3 gives the following elemental analysis in percent by mass: Na = 32.08%, O = 36.01%, Cl = 19.51%. Calculate the percent by mass of each compound in the sample. 시료의 질량 = 100 g 이라 가정하면, 각 성분 원소의 질량 백분율(%) = 각 성분 원소의 질량(g) 각 성분 원소의 몰수를 계산하면, > Na의 몰수 = 32.08 g / (22.99 g/mol) = 1.395 mol ( 참고 https://ywpo.. 2024. 4. 20.
lead tin 3.50 g HNO3 1.57 g PbSO4(s) lead tin 3.50 g HNO3 1.57 g PbSO4(s) A 3.50 g ofan alloy which contains only lead and tin is dissolved in hot HNO3. Excess sulfuric acid is added to this solution and 1.57 g of PbSO4(s) is obtained. a) Write the net ionic equation for the formation of PbSO4(s). b) Assuming all the lead in the alloy reacted to form PbSO4, what was the amount, in grams, of lead and tin in the alloy respectively? n.. 2024. 4. 20.
yield 67.0% N2H4 mass 26.57 g N2 react 4.65 g H2 yield 67.0% N2H4 mass 26.57 g N2 react 4.65 g H2 For the reaction N2(g) + 2H2(g) → N2H4(l), if the percent yield for this reaction is 67.0%, what is the actual mass of hydrazine (N2H4) produced when 26.57 g of nitrogen reacts with 4.65 g of hydrogen? 각 반응물의 몰수를 계산하면, 26.57 g / (28 g/mol) = 0.9489 mol N2 ( 참고 https://ywpop.tistory.com/7738 ) 4.65 g / (2 g/mol) = 2.325 mol H2 N2(g) + 2H2(g) → N2H4.. 2024. 4. 19.
1.00 atm 295 K 2.25 L CO2 C6H12O6 1.00 atm 295 K 2.25 L CO2 C6H12O6 Yeast and other organisms can convert glucose (C6H12O6) to ethanol (CH3CH2OH) by a process called alcoholic fermentation. The net reaction is C6H12O6(s) → 2C2H5OH(l) + 2CO2(g) Calculate the mass of glucose required to produce 2.25 L of CO2 measured at P = 1.00 atm and T = 295 K. PV = nRT 로부터, ( 참고 https://ywpop.tistory.com/3097 ) CO2의 몰수를 계산하면, n = PV / RT = [(1.. 2024. 4. 19.
Calicheamicin C55H74IN3O21S4 5.0×10^(-9) M 25.00 mL Calicheamicin C55H74IN3O21S4 5.0×10^(-9) M 25.00 mL Calicheamicin gamma-1, C55H74IN3O21S4, is one of the most potent antibiotics known: one molecule kills one bacterial cell. Describe how you would (carefully!) prepare 25.00 mL of an aqueous calicheamicin gamma-1 solution that could kill 1.0×10^8 bacteria, starting from a 5.00×10^(-9) M stock solution of the antibiotic. 칼리키아마이신 감마-1(Calicheamici.. 2024. 4. 14.
0.300 M NaOH 105.0 mL 0.060 M AlCl3 150.0 mL 0.300 M NaOH 105.0 mL 0.060 M AlCl3 150.0 mL A solution of 105.0 mL of 0.300 M NaOH is mixed with a solution of 150.0 mL of 0.060 M AICI3. a) Write the balanced chemical equation for the reaction that occurs. b) What precipitate forms? c) What is the limiting reactant? d) How many grams of this precipitate form? e) What is the concentration of each ion that remains in solution? a) Write the bala.. 2024. 4. 13.
2.50 mol Ba(OH)2의 질량 2.50 mol Ba(OH)2의 질량 ① 물질의 몰질량을 계산한다. ( 참고 https://ywpop.tistory.com/16840 ) ( 참고 https://ywpop.tistory.com/18326 ) ② 몰수를 질량으로 환산한다. ( 참고: n=W/M https://ywpop.tistory.com/7738 ) ① Ba(OH)2의 몰질량 = 171.34 g/mol 이므로, ② 2.50 mol × (171.34 g/mol) = 428.35 g 답: 428 g [ 관련 글 https://ywpop.tistory.com/24730 ] 10.0 g KHCO3의 몰수 [키워드] nw 기준, 몰수를 질량으로 기준 2024. 4. 11.
SO2의 조성 백분율 SO2의 조성 백분율 > SO2의 몰질량 = (32) + 2(16) = 64 g/mol ( 참고 https://ywpop.tistory.com/16840 ) > S의 조성 백분율 = [32 / 64] × 100 = 50% S ( 참고 https://ywpop.tistory.com/12958 ) > O의 조성 백분율 = [2(16) / 64] × 100 = 50% O [ 관련 글 https://ywpop.tistory.com/5171 ] CO2의 조성 백분율 [키워드] SO2의 조성 백분율 기준 2024. 4. 11.
0.000 988 M KMnO4 21.08 mL 10.0 mL Ca^2+ mg 0.000 988 M KMnO4 21.08 mL 10.0 mL Ca^2+ mg Calcium levels in blood can be determined by adding oxalate ion to precipitate calcium oxalate, CaC2O4, followed by dissolving the precipitate in aqueous acid and titrating the resulting oxalic acid (H2C2O4) with KMnO4: 5H2C2O4(aq) + 2MnO4^-(aq) + 6H^+(aq) → 10CO2(g) + 2Mn^2+(aq) + 8H2O(l) How many milligrams of Ca^2+ are present in 10.0 mL of blood if.. 2024. 4. 11.
10.0 g KHCO3의 몰수 10.0 g KHCO3의 몰수 ① 물질의 몰질량을 계산한다. ( 참고 https://ywpop.tistory.com/16840 ) ( 참고 https://ywpop.tistory.com/18326 ) ② 질량을 몰수로 환산한다. ( 참고: n=W/M https://ywpop.tistory.com/7738 ) ① KHCO3의 몰질량 = 100.12 g/mol 이므로, ② 10.0 g / (100.12 g/mol) = 0.09988 mol 답: 0.0999 mol [ 관련 글 https://ywpop.tistory.com/24733 ] 2.50 mol Ba(OH)2의 질량 [키워드] nw 기준, 질량을 몰수로 기준 2024. 4. 11.
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