반응형 일반화학/[15장] 화학 평형157 평형상수식. 2NBr3(s) ⇌ N2(g) + 3Br2(g) 평형상수식. 2NBr3(s) ⇌ N2(g) + 3Br2(g) Write expressions for K and Kp for the following reactions. 2NBr3(s) ⇌ N2(g) + 3Br2(g) --------------------------------------------------- ▶ 참고: 평형상수식 쓰기 [ https://ywpop.tistory.com/7136 ] ▶ 참고: 순수한 고체/액체의 활동도 = 1 [ https://ywpop.tistory.com/3760 ] --------------------------------------------------- K = [N2] [Br2]^3 Kp = (P_N2) (P_Br2)^3 2022. 1. 3. 평형상수식. 2NH3(g) + CO2(g) ⇌ N2CH4O(s) + H2O(g) 평형상수식. 2NH3(g) + CO2(g) ⇌ N2CH4O(s) + H2O(g) Write expressions for K and Kp for the following reactions. 2NH3(g) + CO2(g) ⇌ N2CH4O(s) + H2O(g) --------------------------------------------------- ▶ 참고: 평형상수식 쓰기 [ https://ywpop.tistory.com/7136 ] ▶ 참고: 순수한 고체/액체의 활동도 = 1 [ https://ywpop.tistory.com/3760 ] --------------------------------------------------- K = [H2O] / [NH3]^2 [CO2] Kp = (P_H2O) / .. 2022. 1. 3. Kc 계산. 2SO2(g) + O2(g) ⇌ 2SO3(g) Kc 계산. 2SO2(g) + O2(g) ⇌ 2SO3(g) At a certain temperature the following reactions have the constants shown: 1) S(s) + O2(g) ⇌ SO2(g) ... Kc1 = 4.2×10^52 2) 2S(s) + 3O2(g) ⇌ 2SO3(g) ... Kc2 = 9.8×10^128 Calculate the equilibrium constant Kc for the following reaction at that temperature: 2SO2(g) + O2(g) ⇌ 2SO3(g) --------------------------------------------------- ▶ 참고: 이론적 평형상수 [ https://ywpop.t.. 2021. 12. 16. COBr2(g) ⇌ CO(g) + Br2(g) 73℃ Kc 0.190 2.00 L COBr2 0.0500 mol COBr2(g) ⇌ CO(g) + Br2(g) 73℃ Kc 0.190 2.00 L COBr2 0.0500 mol Carbonyl bromide decomposes to carbon monoxide and bromine. COBr2(g) ⇌ CO(g) + Br2(g) Kc is 0.190 at 73℃. If you place 0.0500 mol of COBr2 in a 2.00 L flask and heat it to 73℃, what are the equilibrium concentrations of COBr2, CO, and Br2? What percentage of the original COBr2 decomposed at this temperature? -------------------------.. 2021. 12. 12. 이론적 평형상수. H(g) + Br(g) ⇌ HBr(g) 이론적 평형상수. H(g) + Br(g) ⇌ HBr(g) 500 K에서 1) H2(g) + Br2(g) ⇌ 2HBr(g) ... Kp = 7.9×10^11 2) H2(g) ⇌ 2H(g) ... Kp = 4.8×10^(-41) 3) Br2(g) ⇌ 2Br(g) ... Kp = 2.2×10^(-15) H와 Br 원자가 반응하여 HBr을 생성하는 반응의 Kp를 계산하시오. --------------------------------------------------- ▶ 참고: 이론적 평형상수 [ https://ywpop.tistory.com/4154 ] --------------------------------------------------- ▶ 참고: 헤스의 법칙 [ https://ywpop.tistory... 2021. 12. 11. C6H5COOH(aq) + CH3COO^-(aq) ⇌ C6H5COO^-(aq) + CH3COOH(aq) is 3.6 C6H5COOH(aq) + CH3COO^-(aq) ⇌ C6H5COO^-(aq) + CH3COOH(aq) is 3.6 The equilibrium constant for the reaction C6H5COOH(aq) + CH3COO^-(aq) ⇌ C6H5COO^-(aq) + CH3COOH(aq) is 3.6 at 25℃. If Ka for CH3COOH is 1.8×10^(-5), what is the acid dissociation constant for C6H5COOH? --------------------------------------------------- ▶ 참고: 이론적 평형상수 [ https://ywpop.tistory.com/4154 ] -----------------------------.. 2021. 12. 7. 25℃ Kc = 7.0×10^25 2SO2(g) + O2(g) ⇌ 2SO3(g) 25℃ Kc = 7.0×10^25 2SO2(g) + O2(g) ⇌ 2SO3(g) 25℃에서 다음 반응에 대하여 Kc = 7.0×10^25 이다. 2SO2(g) + O2(g) ⇌ 2SO3(g) 반응 SO3(g) ⇌ SO2(g) + 1/2 O2(g)의 Kc 값을 구하시오. --------------------------------------------------- ▶ 참고: 이론적 평형상수 [ https://ywpop.tistory.com/4154 ] --------------------------------------------------- ×(1/2) 하고, 역반응을 취했으므로, Kc = 1 / (7.0×10^25)^(1/2) = 1.2×10^(-13) 답: 1.2×10^(-13) 2021. 12. 2. Kc 계산. H2O(g) + CO(g) ⇌ CO2(g) + H2(g) Kc 계산. H2O(g) + CO(g) ⇌ CO2(g) + H2(g) At 25℃, the following reactions have the equilibrium constants noted to the right of their equations. 1) 2CO(g) + O2(g) ⇌ 2CO2(g) ... Kc = 3.3×10^91 2) 2H2(g) + O2(g) ⇌ 2H2O(g) ... Kc = 9.1×10^80 위 자료를 이용하여 다음 반응의 Kc를 계산하시오. H2O(g) + CO(g) ⇌ CO2(g) + H2(g) ... Kc = ? --------------------------------------------------- ▶ 참고: 이론적 평형상수 [ https://ywpop.tistory... 2021. 12. 2. 이론적 평형상수. H2N-CH2-COOH ⇌ +H3N-CH2-COO^- 이론적 평형상수. H2N-CH2-COOH ⇌ +H3N-CH2-COO^- 아미노산인 글리신(H2N-CH2-COOH)은 물속에서 와 같은 평형을 이룬다. H2N-CH2-COOH + H2O ⇌ H2N-CH2-COO^- + H3O^+ ... Ka = 4.3×10^(-3) H2N-CH2-COO^- + H2O ⇌ +H3N-CH2-COO^- + OH^- ... Kb = 6.0×10^(-5) 쯔비터 이온을 형성하는 다음 반응의 평형 상수를 구하면, H2N-CH2-COOH ⇌ +H3N-CH2-COO^- --------------------------------------------------- ▶ 참고: 쯔비터 이온(zwitterion) [ https://ywpop.tistory.com/7992 ] ▶ 참고: 이론적 평.. 2021. 11. 25. 420℃ H2(g) + CO2(g) ⇌ H2O(g) + CO(g) K = 0.10 420℃ H2(g) + CO2(g) ⇌ H2O(g) + CO(g) K = 0.10 H2(g) + CO2(g) ⇌ H2O(g) + CO(g) K = 0.10 (420℃에서) H2와 CO2의 처음농도는 각각 0.050 M이었다고 하자. 평형상태에서의 반응물과 생성물의 농도는? --------------------------------------------------- ICE 도표를 작성하면, 평형에서, [H2] = [CO2] = (0.050 – x) M [H2O] = [CO] = x M K = [H2O] [CO] / [H2] [CO2] 0.10 = x^2 / (0.050 – x)^2 0.10 = [x / (0.050 – x)]^2 x / (0.050 – x) = 0.10^(1/2) = 0.316 x = 0... 2021. 11. 18. 이전 1 ··· 5 6 7 8 9 10 11 ··· 16 다음 반응형
