반응형 일반화학/[15장] 화학 평형191 0.200 mol of H2S is placed in an empty 1.00 L container 0.200 mol of H2S is placed in an empty 1.00 L container The equilibrium constant, K, is 4.20×10^(-6) for the following reaction: 2H2S(g) ⇌ 2H2(g) + S2(g) Find the equilibrium concentrations of all entities when 0.200 mol of H2S(g) is placed in a 1.00 L container. --------------------------------------------------- [H2S] = 0.200 mol / 1.00 L = 0.200 M ICE 도표를 작성하면, ............... 2H2S(g) ... ⇌ ... 2022. 12. 29. 4.00 mol H2(g), 4.00 mol F2(g), 6.00 mol HF(g) 4.00 mol H2(g), 4.00 mol F2(g), 6.00 mol HF(g) When hydrogen reacts with fluorine, hydrogen fluoride is formed according to the following equation: H2(g) + F2(g) ⇌ 2HF(g) The equilibrium constant, K, is 1.15×10^2 at SATP. Calculate the concentrations of all entities at equilibrium if 4.00 mol H2(g), 4.00 mol F2(g), and 6.00 mol HF(g) are initially placed into a 2.00 L container. ----------------.. 2022. 12. 28. 2NO2(g) ⇌ N2O4(g) K = 1.15 NO2 0.650 mol/L 2NO2(g) ⇌ N2O4(g) K = 1.15 NO2 0.650 mol/L In a sealed container,nitrogen dioxide is in equilibrium with dinitrogen tetroxide.2NO2(g) ⇌ N2O4(g) ... K = 1.15 at 55°CFind the equilibrium concentrationsof nitrogen dioxide and dinitrogen tetroxideif the initial concentration of nitrogen dioxide is 0.650 mol/L. ICE 도표를 작성하면, ............. 2NO2(g) . ⇌ . N2O4(g)초기(M) . 0.650 ....... 2022. 12. 28. H2(g) + I2(g) ⇌ 2HI(g) Kc 100.0 H2 1.0 mol 10.0 L H2(g) + I2(g) ⇌ 2HI(g) Kc 100.0 H2 1.0 mol 10.0 L 평형상수 응용. 평형에 도달했을 때 HI의 농도 H2(g) + I2(g) ⇌ 2HI(g) ... Kc = 100.0 온도 T에서 H2 1.0 mol과 I2 1.0 mol이 10.0 L 용기에서 반응하여 평형에 도달하였을 때, HI의 농도(M)는? 단, 온도는 T로 일정. --------------------------------------------------- [H2] = [I2] = 1.0 mol / 10.0 L = 0.10 M = C(초기농도) Kc = [HI]^2 / [H2][I2] = (2x)^2 / (C–x)^2 ( 참고 https://ywpop.tistory.com/6300 ) (2x)^2 / (0.10.. 2022. 12. 15. 암모니아 르샤틀리에 N2(g) + 3H2(g) ⇌ 2NH3(g) ★ 암모니아 르샤틀리에 N2(g) + 3H2(g) ⇌ 2NH3(g) --------------------------------------------------- ▶ 참고: 르샤틀리에 원리 [ https://ywpop.tistory.com/2685 ] --------------------------------------------------- N2(g) + 3H2(g) ⇌ 2NH3(g) 평형 상태에서, ① 압력을 낮추면, 역반응 진행. > 압력이 증가하려면, 기체 몰수 증가 쪽으로. ---> Yes ( 참고 https://ywpop.tistory.com/2686 ) ② 압력을 높이면, 정반응 진행. > 압력이 감소하려면, 기체 몰수 감소 쪽으로. ---> Yes ③ 질소를 주입하면, 정반응 진행. > 반응물이.. 2022. 12. 15. CO(g) + H2O(g) ⇌ CO2(g) + H2(g) 500℃ equilibrium constant 3.9 CO(g) + H2O(g) ⇌ CO2(g) + H2(g) 500℃ equilibrium constant 3.9 An important step in the industrial production of hydrogen is the reaction of carbon monoxide with water: CO(g) + H2O(g) ⇌ CO2(g) + H2(g) a) Use the law of mass action to write the equilibrium expression for this reaction. b) At 500℃, the equilibrium constant for this reaction is 3.9. Suppose that the equilibrium partial pressures of .. 2022. 12. 12. NH4HS(s) ⇌ NH3(g) + H2S(g) Kp = 0.108 at 25℃ NH4HS(s) ⇌ NH3(g) + H2S(g) Kp = 0.108 at 25℃ Solid ammonium hydrogen sulfide, NH4HS, dissociates appreciably even at room temperature forming ammonia, NH3, and hydrogen sulfide, H2S, gases. What is the total pressure at equilibrium if solid NH4HS is placed in an evacuated container and allowed to reach equilibrium? Kp = 0.108 at 25℃. --------------------------------------------------- ICE 도표를 작성.. 2022. 12. 8. 평형상수와 속도상수. Kc = kf / kr 평형상수와 속도상수. Kc = kf / kr 다음 평형 반응에서,A ⇌ B 평형 상수, K_c = [B] / [A]( 참고 https://ywpop.tistory.com/7136 ) 정반응 속도, rate_f = k_f [A]( 참고 https://ywpop.tistory.com/26 ) 역반응 속도, rate_r = k_r [B] 평형에서,rate_f = rate_r 이므로,k_f [A] = k_r [B] [B] / [A] = k_f / k_r K_c = [B] / [A] 이므로,K_c = k_f / k_r( 참고 https://ywpop.tistory.com/22778 ) 평형상수 = 정반응 속도상수 / 역반응 속도상수 .. 2022. 12. 6. 평형 상수가 온도에만 영향을 받는 이유 평형 상수가 온도에만 영향을 받는 이유 왜 평형 상수는 온도에만 영향을 받나? Why is equilibrium constant affected by the temperature? Why does only Temp affect K? --------------------------------------------------- ▶ 참고: 르 샤틀리에의 원리. 온도 변화 [ https://ywpop.tistory.com/2691 ] --------------------------------------------------- 르 샤틀리에의 원리로 설명이 가능하다. [ https://ywpop.tistory.com/2691 ] ▶ 온도를 변화시켰을 때 평형 상수 값의 변화를 정리하면, ① 발열 반응일 때, 온도를.. 2022. 11. 29. NH4(NH2CO2)(s) ⇌ 2NH3(g) + CO2(g) Kp = 0.0596 NH4(NH2CO2)(s) ⇌ 2NH3(g) + CO2(g) Kp = 0.0596 For the decomposition of ammonium carbamate NH4(NH2CO2)(s) ⇌ 2NH3(g) + CO2(g) Kp = 0.0596 at a certain temperature. A solid sample of ammonium carbamate is introduced into an evacuated container and at equilibrium some solid remains in the container. What is the total pressure in the container? --------------------------------------------------- 분해 반.. 2022. 11. 17. 이전 1 ··· 4 5 6 7 8 9 10 ··· 20 다음 반응형
