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화학/원소(연소)분석281

250.0 g benzene 3.84 g C4H2N 0.614℃ 250.0 g benzene 3.84 g C4H2N 0.614℃ 250.0 g benzene 속에 3.84 g C4H2N이 들어있는 용액은 벤젠의 어는점을 0.614℃ 낮게 한다. C4H2N의 분자식은 무엇인가? A solution containing 3.84 g C4H2N in 250.0 g benzene lowers the freezing point of benzene by 0.614℃. What is the molecular formula of C4H2N? --------------------------------------------------- ΔTf = Kf × m 이므로, ( 참고 https://ywpop.tistory.com/1920 ) m = ΔTf / Kf = (0.614 ℃) / (5.. 2022. 11. 13.
실험식. hydrate 20.3% Cu 8.95% Si 36.3% F 34.5% H2O 실험식. hydrate 20.3% Cu 8.95% Si 36.3% F 34.5% H2O A certain hydrate is found to have the composition: 20.3% Cu, 8.95% Si, 36.3% F and 34.5% H2O. What is the empirical formula of this hydrate? --------------------------------------------------- ▶ 참고: 원소분석 [ https://ywpop.tistory.com/64 ] --------------------------------------------------- 시료의 질량 = 100 g 이라 가정하면, > 20.3 g Cu > 8.95 g Si > 36.3 g F .. 2022. 11. 9.
실험식. 74.95% C, 11.74% H, 13.31% O 실험식. 74.95% C, 11.74% H, 13.31% O A compound contains 74.95% C, 11.74% H, and 13.31% O. Determine the empirical formula of this compound. --------------------------------------------------- ▶ 참고: 원소분석 [ https://ywpop.tistory.com/64 ] --------------------------------------------------- 각 성분의 몰수 계산 > 74.95 g / (12.0107 g/mol) = 6.24027 mol C > 11.74 / 1.00794 = 11.64752 mol H > 13.31 / 15.9994 = 0.. 2022. 10. 28.
40.0% C, 6.7% H, 53.3% O, mol mass 60 g/mol 40.0% C, 6.7% H, 53.3% O, mol mass 60 g/mol A compound is 40.0% carbon, 6.7% hydrogen and 53.3% oxygen. Determine the empirical formula and molecular formula if actual molar mass of compound is 60 g/mol. --------------------------------------------------- ▶ 참고: 원소분석 [ https://ywpop.tistory.com/64 ] --------------------------------------------------- 각 성분의 몰수 계산 > C의 몰수 = 40.0 / 12 = 3.33 mol > H.. 2022. 10. 10.
12.8 g 탄소와 54.0 g 불소가 포함되어 있는 화합물의 실험식 12.8 g 탄소와 54.0 g 불소가 포함되어 있는 화합물의 실험식 12.8 g C 54.0 g F --------------------------------------------------- ▶ 참고: 원소분석 [ https://ywpop.tistory.com/64 ] --------------------------------------------------- [1] 각 성분의 몰수 계산 > 12.8 g / (12 g/mol) = 1.0667 mol C > 54.0 / 19 = 2.8421 mol F [2] 몰수의 가장 작은 정수비 계산 C : F = 1.0667 : 2.8421 = 1.0667/1.0667 : 2.8421/1.0667 = 1 : 2.6644 = 3 : 8 ---> 실험식 = C3 F.. 2022. 10. 5.
mol mass 438.8 g/mol 0.634 g C 0.088 g H 0.560 g S mol mass 438.8 g/mol 0.634 g C 0.088 g H 0.560 g S The molar mass of a compound is 438.8 g/mol. A sample of the compound contains 0.634 g of carbon, 0.088 g of hydrogen, and 0.560 g of sulfur. Determine the molecular formula of the compound. --------------------------------------------------- ▶ 참고: 원소분석 [ https://ywpop.tistory.com/64 ] --------------------------------------------------- [1] 각 성분.. 2022. 10. 5.
40.0% C, 6.7% H, 53.3% O water 109 g 2.90 g –0.41℃ 40.0% C, 6.7% H, 53.3% O water 109 g 2.90 g –0.41℃ 비이온성 용질의 백분율 조성이 40.0% C, 6.7% H, 53.3% O. 물 109 g에 이 물질 2.90 g 녹아있는 용액이 –0.41℃에서 언다면, 이 물질의 분자식은? 물의 Kf = 1.86 --------------------------------------------------- ▶ 참고: 원소분석 [ https://ywpop.tistory.com/64 ] --------------------------------------------------- 백분율 조성이 40.0% C, 6.7% H, 53.3% O인 물질의 실험식 = CH2O ---> 실험식량 = (12) + 2(1) + (16) = 30 ( .. 2022. 6. 15.
caminic acid C 53.66% H 4.09% 0.3602 g 0.0406 M NaOH 18.02 mL caminic acid C 53.66% H 4.09% 0.3602 g 0.0406 M NaOH 18.02 mL Carminic acid, a naturally occurring red pigment extracted from the cochineal insect, contains only carbon, hydrogen, and oxygen. It was commonly used as a dye in the first half of the nineteenth century. It is 53.66% C and 4.09% H by mass. A titration required 18.02 mL of 0.0406 M NaOH to neutralize 0.3602 g carminic acid. Assuming t.. 2022. 6. 10.
자철광 시료 3.85 g에는 철 2.79 g이 함유 자철광 시료 3.85 g에는 철 2.79 g이 함유 순수한 자철광은 철-산소의 이성분 화합물로 구성된 광물이다. 자철광 시료 3.85 g에는 철 2.79 g이 함유되어 있다. 자철광의 실험식은 무엇인가? Pure magnetite is a mineral composed of an iron-oxygen binary compound. A 3.85 g sample of magnetite is composed of 2.79 g of iron. What is the empirical formula of the magnetite? --------------------------------------------------- ▶ 참고: 원소분석 [ https://ywpop.tistory.com/64 ] --------.. 2022. 6. 8.
Fe 3.524 g S 3.034 g O 4.542 g Fe 3.524 g S 3.034 g O 4.542 g Determine the empirical formula of a compound if a sample of the compound contains 3.524 g iron, 3.034 g sulfur, and 4.542 g of oxygen. --------------------------------------------------- ▶ 참고: 원소분석 [ https://ywpop.tistory.com/64 ] --------------------------------------------------- (1) 각 성분의 몰수 계산 > Fe: 3.524 g / (55.8450 g/mol) = 0.063103 mol Fe > S: 3.034 / 32.0.. 2022. 5. 28.
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