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화학/원소(연소)분석301

30.0 g CHO sample 44.0 g CO2 18.0 g H2O 30.0 g CHO sample 44.0 g CO2 18.0 g H2O 30.0 mg CHO sample 44.0 mg CO2 18.0 mg H2O Upon combustion, a 30.0 g sample of a compound containing only carbon, hydrogen, and oxygen produces 44.0 g of carbon dioxide and 18.0 g of water. Find the empirical formula of the compound. [참고] CHO 연소분석 [ https://ywpop.tistory.com/2854 ] ① 각 성분의 질량 계산 > C의 질량 = 44.0 g × (12/44) = 12.0 g > H의 질량 = 18.0 g × (2/18).. 2024. 3. 17.
hydrocarbon 7.2 g H2O 7.2 L CO2 empirical formula hydrocarbon 7.2 g H2O 7.2 L CO2 empirical formula 어떤 탄화수소 완전연소 시, 7.2 g H2O와 7.2 L CO2가 생성되었다면, 이 탄화수소의 실험식은? The hydrocarbon burns completely, producing 7.2 grams of water and 7.2 liters of CO2 gas at standard condition (1 mole of a gas occupies 22.4 liters at STP). What is the empirical formula of the hydrocarbon? [참고] CH 연소분석. CH 원소분석 [ https://ywpop.tistory.com/9606 ] 탄화수소에 포함된 C 원자는 전부 CO2로.. 2024. 3. 8.
CHO 5.00 g 아세트산 7.33 g CO2, 3.00 g H2O mass 60 CHO 5.00 g 아세트산 7.33 g CO2, 3.00 g H2O mass 60 5.00 g of an organic compound containing C, H and O on combustion yielded 7.33 g CO2 and 3.00 g H2O. If 1 mole of compound weighs 60, then molecular formula of compound is --------------------------------------------------- 답: 실험식 = CH2O, 분자식 = C2H4O2 [Blogger 블로그스팟] [ https://ywpop.blogspot.com/2023/10/cho-500-g-733-g-co2-300-g-h2o-mass-60.html ] [.. 2023. 11. 30.
85.62% C molar mass 84.16 g/mol molecular formula 85.62% C molar mass 84.16 g/mol molecular formula C와 H로만 이루어진 화합물에서 85.62%의 C가 발견되었다. 분자량이 84.16 g/mol이라면 화합물의 분자식을 결정하시오. A compound containing only carbon and hydrogen was found to be 85.62% carbon. Determine the molecular formula of the compound if its molar mass is 84.16 g/mol. --------------------------------------------------- 답: C6H12 [Blogger 블로그스팟] [ https://ywpop.blogspot.com/2023/10/8.. 2023. 10. 31.
2.500 g sample CHO 3.689 g CO2 1.500 g H2O 2.500 g sample CHO 3.689 g CO2 1.500 g H2O 2.500 g sample containing C, H, O produces 3.689 g CO2, 1.500 g H2O --------------------------------------------------- [1] 1.007 g C [2] 0.168 g H [3] 1.325 g O [Blogger 블로그스팟] [ https://ywpop.blogspot.com/2023/10/2500-g-sample-cho-3689-g-co2-1500-g-h2o.html ] [키워드] CHO 연소분석 기준, CHO 원소분석 기준, CHO 연소분석 사전, CHO 원소분석 사전 M2(CO3)3 화합물 속 금속 Which metal (ion) .. 2023. 10. 9.
원소분석. X Cl mass 13.10% X six times 원소분석. X Cl mass 13.10% X six times You find a compound composed only of element X and chlorine, and you know that the compound is 13.10% X by mass. Each molecule of the compound contains six times as many chlorine atoms as X atoms. What is element X? --------------------------------------------------- ▶ 참고: 원소분석 [ https://ywpop.tistory.com/64 ] ---------------------------------------------------.. 2023. 7. 3.
4.07% H, 24.27% C, 71.65% Cl mol mass 98.96 g 4.07% H, 24.27% C, 71.65% Cl mol mass 98.96 g A compound contains 4.07% H, 24.27% C and 71.65% Cl. Its molar mass is 98.96 g. What are its empirical and molecular formulas? --------------------------------------------------- ▶ 참고: 원소 분석 [ https://ywpop.tistory.com/64 ] --------------------------------------------------- 각 성분의 몰수 계산 > 24.27 g / (12.01 g/mol) = 2.02 mol C > 4.07 / 1.008 = 4.04 mol.. 2023. 5. 8.
질량 기준 25% A, 75% B이고 B 원자량은 A의 2배 질량 기준 25% A, 75% B이고 B 원자량은 A의 2배 질량 기준 25% A, 75% B이고, B의 원자량은 A의 2배인 화합물의 실험식 --------------------------------------------------- ▶ 참고: 원소분석 [ https://ywpop.tistory.com/64 ] --------------------------------------------------- A의 원자량 = 1 g/mol 이라 두면, B의 원자량 = 2 g/mol. 각 성분의 몰수 계산 > A의 몰수 = 25 g / (1 g/mol) = 25 mol > B의 몰수 = 75 g / (2 g/mol) = 37.5 mol 몰수의 가장 작은 정수비 계산 A : B = 25 : 37.5 = 25/25.. 2023. 5. 6.
85.5% C, 14.2% H gas 4 g 27℃ 1 atm 3.5 L 85.5% C, 14.2% H gas 4 g 27℃ 1 atm 3.5 L 85.5% 탄소와 14.2% 수소로 된 어떤 기체 화합물 4 g이 27℃ 1기압에서 3.5 L의 부피를 차지한다. 기체의 분자식은? --------------------------------------------------- ▶ 참고: 원소분석 [ https://ywpop.tistory.com/64 ] --------------------------------------------------- 각 성분의 몰수 계산 > 85.5 g / (12 g/mol) = 7.125 mol C > 14.2 / 1 = 14.2 mol H ( 참고 https://ywpop.tistory.com/7738 ) 몰수의 가장 작은 정수비 계산 C : H = .. 2023. 5. 3.
C H N sample 5.250 mg CO2 14.242 mg H2O 4.083 mg C H N sample 5.250 mg CO2 14.242 mg H2O 4.083 mg Nicotine, a component of tobacco, is composed of C, H, and N. A 5.250 mg sample of nicotine was combusted, producing 14.242 mg of CO2 and 4.083 mg of H2O. What is the empirical formula for nicotine? If nicotine has a molar mass of 160±5 g/mol, what is its molecular formula? --------------------------------------------------- ▶ 참고: 원소분석 [ https://y.. 2023. 4. 21.
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