반응형 일반화학/[15장] 화학 평형194 Hydrogen iodide Kc 0.0156 400℃ 0.550 mol HI 2.00 L Hydrogen iodide Kc 0.0156 400℃ 0.550 mol HI 2.00 L Hydrogen iodide decomposes according to the equation 2HI(g) ⇌ H2(g) + I2(g), for which Kc = 0.0156 at 400℃. Suppose 0.550 mol HI is injected into a 2.00 L reaction vessel at 400℃. What is the concentration of HI at equilibrium? [HI] = 0.550 mol / 2.00 L= 0.275 mol/L= 0.275 M ICE 도표를 작성하면,............. 2HI(g) ⇌ H2(g) + I2(g)초기(.. 2024. 10. 5. 15.00 g solid NH4HS is introduced into 500 mL flask at 25°C 15.00 g solid NH4HS is introduced into 500 mL flask at 25°C Suppose 15.00 g of solid ammonium hydrogen sulfide is introduced into a 500. -mL flask at 25°C, the flask is sealed, and the system is allowed to reach equilibrium. What is the partial pressure of ammonia in this flask if Kp = 0.108 at 25°C for the following reaction?NH4HS(s) ⇌ NH3(g) + H2S(g) Kp = (P_NH3) (P_H2S)( 참고 https:/.. 2024. 10. 4. NO 0.095 atm, Cl2 0.171 atm, NOCl 0.28 atm 500.0 K NO 0.095 atm, Cl2 0.171 atm, NOCl 0.28 atm 500.0 K 온도 500 K에서 다음 평형이 이루어졌다.2NO(g) + Cl2(g) ⇌ 2NOCl(g)평형 혼합물에서 세 기체의 부분 압력은NO가 0.095 atm, Cl2가 0.171 atm, NOCl이 0.28 atm이다.a) 500.0 K에서 이 반응의 Kp를 계산하시오.b) 반응 용기의 부피가 5.00 L라고 하고,이 온도에서의 K를 구하시오. The equilibrium 2NO(g) + Cl2(g) ⇌ 2NOCl(g) is established at 500 K. An equilibrium mixture of the three gases has partial pressures of 0.095 atm, .. 2024. 9. 29. 1.374 g H2 70.31 g Br2 2.00 L 700 K 0.566 g H2 1.374 g H2 70.31 g Br2 2.00 L 700 K 0.566 g H2 A mixture of 1.374 g of H2 and 70.31 g of Br2is heated in a 2.00 L vessel at 700 K.These substances react as follows:H2(g) + Br2(g) ⇌ 2HBr(g)At equilibrium the vessel is found to contain 0.566 g of H2.a. Calculate the equilibrium concentrations of H2, Br2 and HBr.b. Calculate Kc. H2 1.374 g과 Br2 70.31 g의 혼합물이2.00 L의 용기 속에서 700 K로 가열되어다음과 같.. 2024. 6. 17. 2SO2(g) + O2(g) ⇌ 2SO3(g) 평형에서 온도 증가 2SO2(g) + O2(g) ⇌ 2SO3(g) 평형에서 온도 증가 Consider the following exothermic reaction at equilibrium: 2SO2(g) + O2(g) ⇌ 2SO3(g) 2SO2(g) + O2(g) ⇌ 2SO3(g) ... ΔH° = –99 kJ/mol Le Chatelier’s principle predicts that an increase in temperature will result in (__). a. no changes in equilibrium partial pressures b. an increase in Keq c. a decrease in the partial pressure of O2 d. a decrease in the partial .. 2024. 4. 18. 2Cl2(g) + 2H2O(g) ⇌ 4HCl(g) + O2(g) 평형에서 O2(g) 몰수 증가 2Cl2(g) + 2H2O(g) ⇌ 4HCl(g) + O2(g) 평형에서 O2(g) 몰수 증가 2Cl2(g) + 2H2O(g) ⇌ 4HCl(g) + O2(g) Le Chatelier’s principle predicts that (__) will result in an increase in the number of moles of O2(g). Select the right answer from the following: 1) Addition of a catalyst 2) Removal of H2O(g) 3) Addition of HCl(g) 4) Increasing the pressure 5) Decreasing the pressure [참고] 르 샤틀리에의 원리 [ https://ywpop.tistor.. 2024. 4. 17. 4.00 L flask 0.200 mol CO(g) 0.400 mol H2(g) 0.100 mol CH3OH(g) 4.00 L flask 0.200 mol CO(g) 0.400 mol H2(g) 0.100 mol CH3OH(g) In a 4.00 L flask, a mixture of 0.200 mol of CO(g) and 0.400 mol of H2(g) were combined in the flask. At equilibrium there was 0.100 mol of CH3OH(g) present, calculate the equilibrium constant Kc for this reaction CO(g) + 2H2(g) ⇌ CH3OH(g) 각 물질의 몰농도를 계산하면, > [CO] = 0.200 mol / 4.00 L = 0.0500 M (초기) > [H2] = 0.400 mol / 4.00 L = 0.1.. 2024. 3. 27. 1000 K 2NO(g) + Br2(g) ⇌ 2NOBr(g) Kc 1.3×10^(-2) 1000 K 2NO(g) + Br2(g) ⇌ 2NOBr(g) Kc 1.3×10^(-2) 4NOBr(g) ⇌ 4NO(g) + 2Br2(g) The equilibrium constant for the reaction 2NO(g) + Br2(g) ⇌ 2NOBr(g) is Kc = 1.3×10^(-2) at 1000 K. Calculate Kc for 4NOBr(g) ⇌ 4NO(g) + 2Br2(g) --------------------------------------------------- 답: Kc = 5917 [Blogger 블로그스팟] [ https://ywpop.blogspot.com/2023/11/1000-k-2nog-br2g-2nobrg-kc-1310-2.html ] [키워드] 이론적 평형상수 기준.. 2023. 12. 15. 430℃ Kp 1.5×10^5 2NO(g) + O2(g) ⇌ 2NO2(g) 430℃ Kp 1.5×10^5 2NO(g) + O2(g) ⇌ 2NO2(g) 2NO(g) + O2(g) ⇌ 2NO2(g). 430℃ 평형상수 1.5×10^5 430℃에서 다음 반응의 평형상수(Kp)는 1.5×10^5 이다. 2NO(g) + O2(g) ⇌ 2NO2(g) 한 실험에서 NO, O2, NO2의 초기 압력은 각각 2.1×10^(-3) atm, 1.1×10^(-2) atm, 0.14 atm이다. Qp를 계산하고, 알짜 반응이 평형에 이르도록 이동할 방향을 예측하시오. --------------------------------------------------- Qp = (P_NO2)^2 / (P_NO)^2 (P_O2) = 4.0×10^5 Qp > Kp 이므로, 역반응, 즉 평형은 반응물 쪽인 왼쪽으로 .. 2023. 11. 25. 472℃ 7.38 atm H2, 2.46 atm N2, 0.166 atm NH3 472℃ 7.38 atm H2, 2.46 atm N2, 0.166 atm NH3472℃ 7.38 bar H2, 2.46 bar N2, 0.166 bar NH3 After a mixture of hydrogen and nitrogen gases in a reaction vesselis allowed to attain equilibrium at 472℃,it is found to contain 7.38 atm H2, 2.46 atm N2, and 0.166 atm NH3.From these data,calculate the equilibrium constant, Kp, for the reactionN2(g) + 3H2(g) → 2NH3(g). -----------------------------.. 2023. 10. 25. 이전 1 2 3 4 5 6 7 ··· 20 다음 반응형