반응형 일반화학/[10장] 기체461 0.7 kg Ar tank 1800 kPa, 40℃ volume 0.7 kg Ar tank 1800 kPa, 40℃ volume A mass of 0.7 kg of argon is maintained at 1800 kPa and 40℃ in a tank. (Assume that the argon is an ideal gas. Molar mass of argon is 39.948 kg/kmol and the universal gas constant is 8.314 kJ/kmol•K.) Determine the volume of the tank. m3 --------------------------------------------------- 700 g / (39.948 g/mol) = 17.5228 mol Ar ( 참고 https://ywpop.tistory.com/7.. 2023. 4. 10. H2 D2 mol fraction 2.014 g/mol H2 D2 mol fraction 2.014 g/mol An equimolar mixture of H2 and D2 effuses through an orifice at a certain temperature. Calculate the composition (in mole fractions) of the gas that passes through the orifice. The molar mass of deuterium is 2.014 g/mol. --------------------------------------------------- > H2의 몰질량 = 2.016 g/mol > D2의 몰질량 = 4.028 g/mol 그레이엄의 법칙 v_H2 / v_D2 = (M_D2 / M_H2)^(1/2) ( 참.. 2023. 4. 10. 3.50 g N2 H2 300 K 1.00 atm 7.46 L mass percent 3.50 g N2 H2 300 K 1.00 atm 7.46 L mass percent A mixture containing nitrogen and hydrogen weighs 3.50 g and occupies a volume of 7.46 L at 300 K and 1.00 atm. Calculate the mass percent of these two gases. Assume ideal-gas behavior. --------------------------------------------------- PV = nRT 로부터, ( 참고 https://ywpop.tistory.com/3097 ) n = PV / RT = [(1.00) (7.46)] / [(0.08206) (300)] = 0.303 mo.. 2023. 4. 10. 27℃, 1기압 8.2 L 혼합기체 A기체 부분압력 0.2 atm 27℃, 1기압 8.2 L 혼합기체 A기체 부분압력 0.2 atm 27℃, 1기압에서 8.2 L의 혼합기체 (A기체 B기체) 가 있다. A기체 부분압력이 0.2 atm 이었다면 B기체는 몇 몰 존재하는가? --------------------------------------------------- PV = nRT 로부터, ( 참고 https://ywpop.tistory.com/3097 ) n = PV / RT = [(1) (8.2)] / [(0.08206) (273.15 + 27)] = 0.3329 mol ---> (A + B)의 몰수 A기체 부분압력 = 0.2 atm 이므로, B기체 부분압력 = 0.8 atm ( 0.2 + 0.8 = 1 atm ) X_B = P_B / P_tot ( B 성분의 몰분율 .. 2023. 4. 8. VT는 일정. 20℃ 1 atm CO2 부피 2배 T2 계산 VT는 일정. 20℃ 1 atm CO2 부피 2배 T2 계산 20℃, 1 atm에서 CO2 기체의 부피를 2배로 증가시키기 위해 온도를 몇 ℃로 올려야 하는가? 단, 압력은 일정. --------------------------------------------------- V1 / T1 = V2 / T2 ( 참고 https://ywpop.tistory.com/1978 ) 여기서, 온도는 섭씨(℃)가 아닌 절대온도(K). T2 = V2 / (V1 / T1) = 2 / (1 / (273+20)) = 586 K 586 – 273 = 313℃ 답: 313℃ 2023. 4. 3. balloon 1.30 L air 24.7℃ nitrogen –78.5℃ volume balloon 1.30 L air 24.7℃ nitrogen –78.5℃ volume Suppose a balloon containing 1.30 L of air at 24.7℃ is placed into a beaker containing liquid nitrogen at –78.5℃. What will the volume of the sample of air become (at constant pressure)? --------------------------------------------------- V1 / T1 = V2 / T2 ( 참고 https://ywpop.tistory.com/1978 ) V2 = V1T2 / T1 = (1.30 × (273.15 – 78.5)) / (273.15 + 2.. 2023. 3. 28. 121 mL CO2 27℃ 1.05 atm 293 mL 1.40 atm 121 mL CO2 27℃ 1.05 atm 293 mL 1.40 atm At what temperature (in ℃) does 121 mL of CO2 at 27℃ and 1.05 atm occupy a volume of 293 mL at a pressure of 1.40 atm? --------------------------------------------------- P1V1 / T1 = P2V2 / T2 ( 참고 https://ywpop.tistory.com/7091 ) T2 = P2V2 / (P1V1 / T1) = 1.40 × 293 / (1.05 × 121 / (273 + 27)) = 969 K 969 – 273 = 696℃ 답: 696℃ 2023. 3. 28. tire 23.0℃ 25.0 L 3.18 atm moles of air tire 23.0℃ 25.0 L 3.18 atm moles of air An automobile tire at 23℃ with an internal volume of 25.0 L is filled with air to a total pressure of 3.18 atm. Determine the number of moles of air in the tire. --------------------------------------------------- PV = nRT 로부터, ( 참고 https://ywpop.tistory.com/3097 ) n = PV / RT = (3.18 × 25.0) / (0.08206 × (273.15 + 23.0)) = 3.27 mol 답: 3.27 mol 2023. 3. 28. PV는 일정. 25℃ 1.00 atm 1.00 dm3 100 cm3 P2 계산 PV는 일정. 25℃ 1.00 atm 1.00 dm3 100 cm3 P2 계산 마취와 심해 잠수에 관한 정보를 얻기 위하여 인간을 포함한 유기체에 대한 고압의 영향을 연구한다. The effect of high pressure on organisms, including humans, is studied to gain information about deep-sea diving and anaesthesia. A sample of air occupies 1.00 dm3 at 25℃ and 1.00 atm. What pressure is needed to compress it to 100 cm3 at this temperature? -------------------------------------------.. 2023. 3. 20. 실제 기체의 부피가 완전 기체 부피보다 12% 작은 경우 실제 기체의 부피가 완전 기체 부피보다 12% 작은 경우 gas at 250 K and 15 atm has a molar volume 12% smaller 250 K, 15 atm 조건에서의 기체의 부피(V_m)가 완전 기체 부피(Vm^perfect)보다 12% 작은 경우 이 조건에서의 압축인자는? A gas at 250 K and 15 atm has a molar volume 12% smaller than that calculated from the perfect gas law. Calculate the compression factor under these conditions and the molar volume of the gas. Which are dominating in the sample, t.. 2023. 3. 11. 이전 1 ··· 3 4 5 6 7 8 9 ··· 47 다음 반응형