실험식. 60.0% C, 4.4% H, and the remainder O

실험식. 60.0% C, 4.4% H, and the remainder O

 

 

Determine the empirical formulas of the compounds with the following compositions by mass:

a) 42.1% Na, 18.9% P, and 39.0% O

b) 18.7% Li, 16.3% C, and 65.0% O

c) 60.0% C, 4.4% H, and the remainder O

 

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▶ 참고: 원소분석 [ https://ywpop.tistory.com/64 ]

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c) 60.0% C, 4.4% H, and the remainder O

 

시료가 100 g 있다고 가정하면,

O의 질량 = 100 - (60.0 + 4.4) = 35.6 g

 

 

C의 몰수 = 60.0 g / (12 g/mol) = 5 mol

H의 몰수 = 4.4 / 1 = 4.4 mol

O의 몰수 = 35.6 / 16 = 2.225 mol

 

 

각 성분 몰수의 가장 작은 정수비를 계산하면,

C : H : O = 5/2.225 : 4.4/2.225 : 2.225/2.225

= 2.247 : 1.978 : 1

= 8.988 : 7.912 : 4

≒ 9 : 8 : 4

---> 실험식 = C9H8O4

---> could be aspirin