실험식 구하기. 67.35 g Ni, 43.46 g O, 23.69 g P

실험식 구하기. 67.35 g Ni, 43.46 g O, 23.69 g P

 

 

Determine the empirical formula for each of the following, using the given masses:

a) a compound containing 26.08 g zinc, 4.79 g carbon, and 19.14 g oxygen

b) a 150.0 g sample of a compound containing 57.66 g carbon, 7.26 g hydrogen, and the rest, chlorine

c) a 75.0 g sample of an oxide of vanadium, containing 42.0 g V and the rest, oxygen

d) a compound containing 67.35 g nickel, 43.46 g oxygen, and 23.69 g phosphorus

 

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▶ 참고: 원소분석 [ https://ywpop.tistory.com/64 ]

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d)

Ni의 몰질량 = 58.69 g/mol

O의 몰질량 = 16.00 g/mol

P의 몰질량 = 30.97 g/mol

 

 

 

각 성분의 몰수를 계산하면,

Ni의 몰수 = 67.35 g / (58.69 g/mol) = 1.1476 mol

( 계산 설명 https://ywpop.tistory.com/7738 )

 

O의 몰수 = 43.46 / 16.00 = 2.7163 mol

P의 몰수 = 23.69 / 30.97 = 0.7649 mol

 

 

 

몰수의 가장 작은 정수비를 계산하면,

Ni : O : P = 1.1476/0.7649 : 2.7163/0.7649 : 0.7649/0.7649

= 1.5003 : 3.5512 : 1

= 3.0006 : 7.1024 : 2

≒ 3 : 7 : 2

---> 실험식 = Ni3O7P2

 

 

답: Ni3O7P2 or Ni3P2O7