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100 mg protein water 10.0 mL osmotic 13.3 mmHg 25℃
100 mg of a protein is dissolved in
just enough water to make 10.0 mL of solution.
If this solution has an osmotic pressure of 13.3 mmHg at 25℃,
what is the molar mass of the protein?
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π = MRT
( 참고 https://ywpop.tistory.com/1921 )
M = π / RT
= (13.3/760) / [(0.08206) (273.15 + 25)]
= 0.00071527 mol/L
(0.00071527 mol/L) (10.0/1000 L)
= 7.1527E–6 mol
0.100 g / 7.1527E–6 mol
( 참고 https://ywpop.tistory.com/7738 )
= 13980.73 g/mol
답: 13981 g/mol
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