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100 mg protein water 10.0 mL osmotic 13.3 mmHg 25℃

by 영원파란 2022. 10. 1.
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100 mg protein water 10.0 mL osmotic 13.3 mmHg 25℃

 

 

100 mg of a protein is dissolved in

just enough water to make 10.0 mL of solution.

If this solution has an osmotic pressure of 13.3 mmHg at 25℃,

what is the molar mass of the protein?

 

---------------------------------------------------

 

π = MRT

( 참고 https://ywpop.tistory.com/1921 )

 

M = π / RT

= (13.3/760) / [(0.08206) (273.15 + 25)]

= 0.00071527 mol/L

 

 

 

(0.00071527 mol/L) (10.0/1000 L)

= 7.1527E–6 mol

 

 

 

0.100 g / 7.1527E–6 mol

( 참고 https://ywpop.tistory.com/7738 )

 

= 13980.73 g/mol

 

 

 

답: 13981 g/mol

 

 

 

 

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