N2O –111.3 ℃ 100 mmHg bp –88.5 ℃ heat kJ/mol

N2O –111.3 ℃ 100 mmHg bp –88.5 ℃ heat kJ/mol

 

 

N2O는 –111.3 ℃에서 P_증기 = 100 mmHg이고,

정상끓는점은 –88.5 ℃이다.

N2O의 증발열은 몇 kJ/mol인가?

 

 

Nitrous oxide, N2O, occasionally used as an anesthetic

by dentists under the name “laughing gas”,

has P_vap = 100 mmHg at –111.3 ℃

and a normal boiling point of –88.5 ℃.

What is the heat of vaporization of nitrous oxide in kJ/mol?

 

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클라우지우스-클라페이롱 식. Clausius-Clapeyron relation

ln(P1/P2) = ΔH_vap/R (1/T2 – 1/T1)

( 참고 https://ywpop.tistory.com/3133 )

 

 

 

> P1 = 100 mmHg, T1 = 273.15 + (–111.3) = 161.85 K

 

> P2 = 760 mmHg, T2 = 273.15 + (–88.5) = 184.65 K

 

 

 

ln(100 / 760) = (ΔH_vap / 8.314) (1/184.65 – 1/161.85)

 

ΔH_vap = ln(100 / 760) / (1/184.65 – 1/161.85) × 8.314

= 22102 J/mol

= 22.1 kJ/mol

 

 

 

 

[키워드] N2O의 증발열 기준문서