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cell potential. 4NH3(g) + 3O2(g) → 2N2(g) + 6H2O(l)

by 영원파란 2020. 12. 28.

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cell potential. 4NH3(g) + 3O2(g) 2N2(g) + 6H2O(l)

 

 

Consider the oxidation of ammonia:

4NH3(g) + 3O2(g) 2N2(g) + 6H2O(l)

 

a) Calculate the ΔG° for the reaction.

 

b) If this reaction were used in a fuel cell,

what would the standard cell potential be?

 

---------------------------------------------------

 

a) Calculate the ΔG° for the reaction.

 

ΔG°_rxn = [생성물들의 ΔG°_f ] - [반응물들의 ΔG°_f ]

( 참고 https://ywpop.tistory.com/7393 )

 

ΔG° = -1356.8 kJ

 

 

 

 

b) If this reaction were used in a fuel cell,

what would the standard cell potential be?

 

> 산화 반쪽 반응식: 4NH3 2N2 + 12H^+ + 12e^-

> 환원 반쪽 반응식: 3O2 + 12H^+ + 12e^- 6H2O

( 참고 https://ywpop.tistory.com/12369 )

---> 이동한 전자의 개수 = 12.

 

 

 

ΔG° = -nFE°

( 참고 https://ywpop.tistory.com/6519 )

 

E° = -ΔG° / nF

= -(-1356800 J/mol) / [(12) (96485 C/mol)]

= 1.17 J/C

= 1.17 V

 

 

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