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화학/원소(연소)분석

실험식. 74.95% C, 11.74% H, 13.31% O

by 영원파란 2022. 10. 28.

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실험식. 74.95% C, 11.74% H, 13.31% O

 

 

A compound contains 74.95% C, 11.74% H, and 13.31% O.

Determine the empirical formula of this compound.

 

 

A compound called cryptomeridiol is among the active ingredients

found in herbs used in traditional Chinese medicine.

It contains 74.95% C, 11.74% H, and 13.31% O.

Determine the empirical formula of this compound.

 

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▶ 참고: 원소분석

[ https://ywpop.tistory.com/64 ]

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각 성분의 몰수 계산

> 74.95 g / (12.0107 g/mol) = 6.24027 mol C

> 11.74 / 1.00794 = 11.64752 mol H

> 13.31 / 15.9994 = 0.8319062 mol O

 

 

 

몰수의 가장 작은 정수비 계산

C : H : O = 6.24027 : 11.64752 : 0.8319062

= 6.24027/0.8319062 : 11.64752/0.8319062 : 0.8319062/0.8319062

= 7.5 : 14 : 1

= 15 : 28 : 2

---> 실험식 = C15 H28 O2

 

 

 

답: C15H28O2

 

 

 

 

[키워드] cryptomeridiol 74.95% C, 11.74% H, 13.31% O cryptomeridiol dic

 

[FAQ] [①23/04/29]

 

 

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