0.08670 M NaI 25.00 mL + 0.05100 M AgNO3. b) equivalence point

0.08670 M NaI 25.00 mL + 0.05100 M AgNO3. b) equivalence point

 

 

A 25.00 mL of 0.08670 M NaI is titrated with 0.05100 M AgNO3.

Calculate pAg^+ following the addition of the given volumes of AgNO3.

The Ksp of AgI is 8.3×10^(-17).

a) 37.50 mL

b) equivalence point

c) 47.30 mL

 

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Ag^+(aq) + I^-(aq) → AgI(s)

Ag^+ : I^- = 1 : 1 몰(mol) 비로 반응.

 

 

 

M1V1 = M2V2

( 참고 https://ywpop.tistory.com/4689 )

 

(0.05100 M) (? mL) = (0.08670 M) (25.00 mL)

 

? = (0.08670) (25.00) / (0.05100) = 42.5 mL

---> 당량점

 

 

 

 

b) equivalence point. 당량점에서

모든 I^-(aq)는 AgI(s)로 침전.

 

 

 

Ksp = [Ag^+] [I^-] = (s) (s) = s^2

( 참고 https://ywpop.tistory.com/8434 )

 

s = (Ksp)^(1/2)

= (8.3×10^(-17))^(1/2)

= 9.11×10^(-9) M = [Ag^+]

 

 

 

pAg^+ = –log[Ag^+]

= –log(9.11×10^(-9))

= 8.04

 

 

 

 

a) 37.50 mL [ https://ywpop.tistory.com/21256 ]

 

c) 47.30 mL [ https://ywpop.tistory.com/21258 ]

 

 

 

 

[키워드] AgI 침전 적정 기준문서, AgI 침전 적정 사전