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NaOCl pH 6.20 buffer [OCl^-]/[HOCl] ratio
Sodium hypochlorite NaOCl was dissolved
in a solution buffered to pH 6.20.
Find the ratio of [OCl^-]/[HOCl] in this solution.
pKa for hypochloric acid is 7.53
---------------------------------------------------
> HOCl(aq) ⇌ H^+(aq) + OCl^-(aq)
> NaOCl(aq) → Na^+(aq) + OCl^-(aq)
Henderson-Hasselbalch 식
pH = pKa + log([짝염기]/[약산])
( 참고 https://ywpop.tistory.com/1926 )
pH = pKa + log([OCl^-]/[HOCl])
6.20 = 7.53 + log([OCl^-]/[HOCl])
log([OCl^-]/[HOCl]) = 6.20 – 7.53 = –1.33
[OCl^-]/[HOCl] = 10^(–1.33) = 0.0468
답: [OCl^-]/[HOCl] = 0.0468
[키워드] NaOCl pH 6.20 buffer [OCl^-]/[HOCl] pKa 7.53
[FAQ] [①23/01/15] [②23/09/26]
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