C6H12O6 포도당 시료에 탄소 원자가 1.250×10^21 개

C6H12O6 포도당 시료에 탄소 원자가 1.250×10^21 개

 

 

C6H12O6 포도당 시료에 탄소 원자가 1.250×10^21 개 포함되어 있다.

이 시료에 포도당 분자는 몇 몰 있는가?

 

 

A sample of glucose, C6H12O6, contains 1.250×10^21 carbon atoms.

a) How many atoms of hydrogen does it contain?

b) How many molecules of glucose does it contain?

c) How many moles of glucose does it contain?

d) What is the mass of this sample in grams?

 

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(1.250×10^21 개 탄소) × (1개 포도당 / 6개 탄소) × (1 mol / 6.022×10^23 개)

= (1.250×10^21) × (1 / 6) × (1 / (6.022×10^23))

= 0.000345953725... mol

---> 유효숫자 4개에 맞추면,

= 3.460×10^(-4) mol

 

 

 

답: 3.460×10^(-4) mol

 

 

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a) How many atoms of hydrogen does it contain?

C6H12O6

---> C : H = 6 : 12 = 1 : 2

 

2 × (1.250×10^21) = 2.500×10^21 hydrogen atoms

 

 

 

 

b) How many molecules of glucose does it contain?

C6H12O6

---> C6H12O6 : C = 1 : 6

 

(1.250×10^21) / 6 = 2.083×10^20 glucose molecules

 

 

 

 

c) How many moles of glucose does it contain?

> 1 mol = 6.022×10^23 개

( 참고 https://ywpop.tistory.com/6475 )

 

(2.083×10^20 개) (1 mol / (6.022×10^23 개))

= 3.459×10^(-4) mol glucose

 

 

 

 

d) What is the mass of this sample in grams?

> C6H12O6의 몰질량 = 180.16 g/mol

 

(3.459×10^(-4) mol) (180.16 g / 1 mol)

= 0.06232 g

= 6.232×10^(-2) g

( 참고: n=W/M https://ywpop.tistory.com/7738 )

 

 

 

 

[키워드] C6H12O6 1.250×10^21 C atom, glucose C6H12O6 1.250×10^21 carbon atom