분압과 농도, 둘 다 같은 평형상수 식에 있을 수 있는가?
Can both partial pressure and concentration
be in the same equilibrium constant equation?
[참고] 평형상수 식
[ https://ywpop.tistory.com/7136 ]
Q. Can both partial pressure and concentration
be in the same equilibrium constant equation?
분압과 농도, 둘 다 같은 평형상수 식에 있을 수 있는가?
A. Certainly. In cases where both gases and substances in solution participate in the reaction the gases are represented by their partial pressure and the substances in solution by their concentration, which is usually expressed as their molarity.
For example:
Zn^2+(aq) + H2(g) ⇌ Zn(s) + 2H^+(aq)
has equilibrium expression:
K = [H^+]^2 / [Zn^2+] (P_H2)
This would give an equilibrium constant with units.
To eliminate the units each concentration or partial pressure is divided by the value in the standard state (1 M or 1 atm) in order to cancel the units and give a unitless equilibrium constant.
( 참고: 활동도 https://ywpop.tistory.com/2684 )
In an equilibrium with both gases and aqueous solution,
use concentration or partial pressure of the gases
when writing the expression for the equilibrium constant
기체와 수용액, 둘 다 평형에 포함된 경우,
기체의 농도나 부분압력을 사용하여 평형상수 식을 쓴다.
[ 관련 글 https://ywpop.tistory.com/3760 ]
순수한 액체와 고체의 농도가 평형 상수 표현에 포함되지 않는 이유
[ 관련 글 https://ywpop.tistory.com/470786 ]
ratio of [Hb(CO)] to [Hb(O2)] in air 20% O2 and 0.15% CO by volume
[키워드] 기체와 수용액이 모두 포함된 평형상수 식 기준, 수용액과 기체가 모두 포함된 평형상수 식 기준, 분압과 농도가 모두 포함된 평형상수 식 기준, 농도와 분압이 모두 포함된 평형상수 식 기준
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