1100 K Kp = 0.25 2SO2(g) + O2(g) = 2SO3(g) 0.50 atm 0 atm

1100 K Kp = 0.25 2SO2(g) + O2(g) = 2SO3(g) 0.50 atm 0 atm

 

 

At 1100 K, Kp = 0.25 for the reaction

2SO2(g) + O2(g) ⇌ 2SO3(g)

Calculate the equilibrium partial pressures of SO2, O2, and SO3

produced from an initial mixture in which

P_SO2 = P_O2 = 0.50 atm and P_SO3 = 0.

(Hint: If you don’t have a graphing calculator,

then use the method of successive approximations to solve,

as discussed in Appendix 1.4.)

 

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ICE 도표를 작성하면,

 

................. 2SO2(g) . + . O2(g) . ⇌ . 2SO3(g)

초기(atm) . 0.50 ............ 0.50 ......... 0

변화(atm) . –2x ............. –x ............. +2x

평형(atm) . 0.50–2x ...... 0.50–x ...... 2x

 

 

 

Kp = [SO3]^2 / [SO2]^2 [O2]

 

0.25 = (2x)^2 / [(0.50–2x)^2 (0.50–x)]

---> 이것을 계산하면 되는데... 못하겠네...