52.5 J heat 0.500 atm 58.0 L 102.5 J volume

52.5 J heat 0.500 atm 58.0 L 102.5 J volume

 

 

As a system increases in volume,

it absorbs 52.5 J of energy in the form of heat from the surroundings.

The piston is working against a pressure of 0.500 atm.

The final volume of the system is 58.0 L.

What was the initial volume of the system

if the internal energy of the system decreased by 102.5 J?

 

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ΔE = q + w

( 참고 https://ywpop.tistory.com/7219 )

 

 

 

ΔE = –102.5 J

q = +52.5 J

w = –P(V2 – V1)

 

 

 

–102.5 J = (+52.5 J) + [–0.500 atm(58.0 L – V1)]

–155 J = –29 atm•L + 0.500 atm•V1

 

 

 

1 atm•L = 101.325 J 이므로,

( 참고 https://ywpop.tistory.com/6646 )

 

–155 J × (1 atm•L / 101.325 J) = –1.5297 atm•L

 

 

 

–1.5297 atm•L = –29 atm•L + 0.500 atm•V1

27.4703 atm•L = 0.500 atm•V1

 

V1 = 27.4703 / 0.500 = 54.94 L

 

 

 

답: 54.9 L

 

 

 

 

[ 관련 예제 https://ywpop.tistory.com/21166 ] piston 10. L 25 L 210. L*atm work 45 J heat

 

 

 

[키워드] 52.5 J heat 0.500 atm piston work 58.0 L energy 102.5 J ini vol