728x170
PVT는 일정. 부피 계산. 23℃ 1.00 atm 1.00 L He balloon –31℃ 220. torr
A sealed balloon is filled with 1.00 L helium at 23℃ and 1.00 atm.
The balloon rises to a point in the atmosphere
where pressure is 220. torr and the temperature is –31℃.
What is the change in volume of the balloon
as it ascends from 1.00 atm to a pressure of 220. torr?
---------------------------------------------------
P1V1 / T1 = P2V2 / T2
( 참고 https://ywpop.tistory.com/7091 )
V2 = P1V1T2 / P2T1
= [(1.00) (1.00) (273.15 + (–31))] / [(220./760) (273.15 + 23)]
= 2.8246 L
답: 2.82 L
반응형
그리드형(광고전용)
'일반화학 > [10장] 기체' 카테고리의 다른 글
24℃ 840 mmHg N2 2.0 L NO2 mass(g) (0) | 2021.05.11 |
---|---|
전체 압력 4.6 atm 질소 5.4 mol 산소 1.4 mol (0) | 2021.05.10 |
25℃ total pressure 1.00 atm 0.586 g He water 23.8 torr (1) | 2021.05.09 |
20℃ 0.821 atm 32.0 g O2 vol (0) | 2021.05.09 |
이산화탄소 소화약제 44 kg 21기압, 50℃ 부피는 몇 m3 (1) | 2021.05.04 |
20℃, 0.821 atm에서 32.0 g O2 기체가 차지하는 부피 (0) | 2021.05.03 |
VT는 일정. CO gas 25.0℃ 150.0 mL 100.0 mL T(℃)? (2) | 2021.05.01 |
35℃ 355 mL 0.146 g Ne Ar 626 mmHg (0) | 2021.04.28 |
댓글