11.9 g Cl2 is reacted with 12.0 g NaOH

11.9 g Cl2 is reacted with 12.0 g NaOH

 

 

For the reaction 2Cl2(g) + 4NaOH(aq) → 3NaCl(aq) + NaClO2(aq) + 2H2O(l)

11.9 g Cl2 is reacted with 12.0 g NaOH.

How many moles of NaCl are produced?

 

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Cl2의 몰질량 = 70.91 g/mol

11.9 g / (70.91 g/mol) = 0.1678 mol Cl2

( 참고 https://ywpop.tistory.com/7738 )

 

 

 

NaOH의 몰질량 = 40.00 g/mol

12.0 / 40.00 = 0.3 mol NaOH

 

 

 

Cl2 : NaOH = 2 : 4 = 1 : 2 계수비(= 몰수비) 이므로,

0.1678 mol Cl2와 반응하는 NaOH의 몰수를 계산하면,

Cl2 : NaOH = 1 : 2 = 0.1678 mol : ? mol

? = 2 × 0.1678 = 0.3356 mol NaOH

---> NaOH는 이만큼 없다, 부족하다.

---> NaOH가 한계 반응물.

( 참고: 한계 반응물 https://ywpop.tistory.com/3318 )

 

 

 

NaOH : NaCl = 4 : 3 = 0.3 mol : ? mol

? = 3 × 0.3 / 4 = 0.225 mol NaCl

 

 

 

답: 0.225 mol