when 75.5 g of CaO is reacted with 50.0 g of C

when 75.5 g of CaO is reacted with 50.0 g of C

 

 

Determine the mass of CO2 produced

when 75.5 g of CaO is reacted with 50.0 g of C

according to the unbalanced equation

CaO + C → CaC2 + CO2

 

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CaO의 몰질량 = 56.08 g/mol

75.5 g / (56.08 g/mol) = 1.3463 mol CaO

( 참고 https://ywpop.tistory.com/7738 )

 

 

 

50.0 / 12.01 = 4.1632 mol C

 

 

 

균형 맞춘 반응식

2CaO + 5C → 2CaC2 + CO2

 

CaO : C = 2 : 5 계수비(= 몰수비) 이므로,

1.3463 mol CaO와 반응하는 C의 몰수를 계산하면,

CaO : C = 2 : 5 = 1.3463 mol : ? mol

? = 5 × 1.3463 / 2 = 3.3658 mol C

---> C는 이만큼 있다, 남는다.

---> C는 과잉 반응물.

---> CaO가 한계 반응물.

( 참고: 한계 반응물 https://ywpop.tistory.com/3318 )

 

 

 

CaO : CO2 = 2 : 1 = 1.3463 mol : ? mol

? = 1.3463 / 2 = 0.67315 mol CO2

 

 

 

0.67315 mol × (44.01 g/mol) = 29.6 g CO2