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4Fe + 3O2 → 2Fe2O3. 1.45 mol sample of iron
The rusting of iron is represented by the equation 4Fe + 3O2 → 2Fe2O3.
If you have a 1.45 mol sample of iron,
how many moles of Fe2O3 will there be after the iron has rusted completely?
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4Fe + 3O2 → 2Fe2O3
Fe : Fe2O3 = 4 : 2 계수비(= 몰수비) 이므로,
1.45 mol Fe 반응 시 생성되는 Fe2O3의 몰수를 계산하면,
Fe : Fe2O3 = 4 : 2 = 1.45 mol : ? mol
? = 2 × 1.45 / 4 = 0.725 mol Fe2O3
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