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4NH3(g) + 7O2 → 4NO2(g) + 6H2O(g). 5.38 mol of ammonia
Refer to the following equation: 4NH3(g) + 7O2 → 4NO2(g) + 6H2O(g)
How many molecules of NO2 are produced
when 5.38 mol of ammonia is completely reacted?
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NH3 : NO2 = 1 : 1 계수비(= 몰수비) 이므로,
NO2의 몰수 = NH3의 몰수 = 5.38 mol
5.38 mol × (6.022×10^23 개/mol) = 3.24×10^24 개 NO2 분자
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