그레이엄. C2F4 4.6×10^(-6) mol/h BH 5.8×10^(-6) mol/h molar mass

그레이엄. C2F4 4.6×10^(-6) mol/h BH 5.8×10^(-6) mol/h molar mass

 

 

C2F4 has an effusion rate of 4.6×10^(-6) mol/h.

An unknown gas containing boron plus hydrogen

has an effusion rate of 5.8×10^(-6) mol/h

under the same conditions.

 

What is the molar mass of the unknown gas?

If the B:H ratio is 1:1.8,

what is the formula of the compound?

 

 

C2F4 effuses through a barrier at a rate of 4.6×10^(-6) mol/hour,

while an unknown gas effuses at a rate of 5.8×10^(-6) mol/hour.

What is the molar mass of the unknown compound?

 

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> C2F4의 몰질량 = 100.0150 g/mol

 

 

 

그레이엄의 확산 법칙

v_C2F4 / v_BH = sqrt(M_BH / M_C2F4)

( 참고 https://ywpop.tistory.com/3478 )

 

 

 

[ v_C2F4 / v_BH ]^2 = M_BH / M_C2F4

 

M_BH = [ v_C2F4 / v_BH ]^2 × M_C2F4

= [ (4.6×10^(-6)) / (5.8×10^(-6)) ]^2 × 100.02

= 62.91

= 63

 

 

 

 

가장 작은 정수비를 계산하면,

B : H = 1 : 1.8 = 5 : 9

---> B5H9

---> 실험식량 = 5(10.811) + 9(1.008) = 63.13

 

 

 

 

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