Sn^4+ reduced to Sn^2+ by 1.00 C

Sn^4+ reduced to Sn^2+ by 1.00 C

 

 

1.00 C의 전하에 의해서

몇 mol의 Sn^4+가 Sn^2+로 환원되는가?

 

 

How many moles of Sn^4+ are reduced to Sn^2+

by 1.00 C of electric charge?

 

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▶ 참고: 환산인자 [ https://ywpop.tistory.com/3121 ]

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▶ 환산인자

> 1 F = 96485 C / mol e^-

( 참고 https://ywpop.tistory.com/3821 )

 

 

 

Sn^4+ + 2e^- → Sn^2+

---> 1 mol Sn^4+ 환원당 2 mol 전자 이동.

---> 환산인자로 만들면,

---> 1 mol Sn^4+ / 2 mol e^-

또는

---> 2 mol e^- / 1 mol Sn^4+

 

 

 

 

1.00 C × (1 mol e^- / 96485 C) × (1 mol Sn^4+ / 2 mol e^-)

= 1.00 × (1 / 96485) × (1 / 2)

= 5.18×10^(-6) mol Sn^4+

 

 

 

5.18×10^(-6) mol × (10^6 μmol / 1 mol) = 5.18 μmol