수상포집. 24℃ 755 mmHg 500 mL O2 (3% H2O2 분해)

수상포집. 24℃ 755 mmHg 500 mL O2 (3% H2O2 분해)

 

 

A 500. mL sample of O2 gas at 24℃ was prepared by decomposing a 3.0% aqueous solution of hydrogen peroxide, H2O2, in the presence of a small amount of manganese catalyst by the reaction

2H2O2(aq) → 2H2O(g) + O2(g)

 

The oxygen thus prepared was collected by displacement of water. The total pressure of gas collected was 755 mmHg. What is the partial pressure of O2 in the mixture? How many moles of O2 are in the mixture? (The vapor pressure of water at 24℃ is 23 mmHg.)

 

 

혼합물에서 산소 기체의 부분 압력은 얼마인가?

혼합물에 포함된 산소의 몰수는 얼마인가?

 

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전체 압력 = O2의 분압 + H2O의 분압

( 참고 https://ywpop.tistory.com/3490 )

 

O2의 분압 = 755 - 23 = 732 mmHg

 

 

 

PV = nRT

( 참고 https://ywpop.tistory.com/3097 )

 

n = PV / RT

= [(732/760) (0.500)] /[(0.08206) (273.15+24)]

= 0.0197 mol O2

 

 

 

 

[키워드] 24℃ 3% H2O2 O2 500 mL 755 mmHg 23 mmHg