반응형 일반화학/[01장] 서론: 물질과 측정367 fathom 6 ft earth moon 250000 mile fathom 6 ft earth moon 250000 mile A fathom is a unit of length, usually reserved for measure the depth of water. A fathom is approximately 6 ft in length. Take the distance from Earth to the moon to be 250,000 miles, use the given approximation to find the distance in fathoms. [참고] 환산 인자 [ https://ywpop.tistory.com/3121 ] ▶ 환산 인자 > 1 fathom = 6 ft > 1 ft = 0.3048 m > 1 mi = 1609.344 m (250000 m.. 2024. 4. 10. 241.3 g flask water d 1.00 g/cm3 489.1 g chloroform d 1.48 g/cm3 241.3 g flask water d 1.00 g/cm3 489.1 g chloroform d 1.48 g/cm3 An empty Erlenmeyer flask weighs 241.3 g. When filled with water (d = 1.00 g/cm3), the flask and its contents weigh 489.1 g. a) What is the flask’s volume? b) How much does the flask weigh when filled with chloroform (d = 1.48 g/cm3)? a) What is the flask’s volume? 물의 질량 = 489.1 – 241.3 = 247.8 g 물의 밀도 = 1.00 g/cm3 이므로, 물의 부피 = 247.. 2024. 3. 30. 5×10^6 m^-1 을 cm^-1 로 환산 5×10^6 m^-1 을 cm^-1 로 환산 [참고] 환산 인자 [ https://ywpop.tistory.com/3121 ] 5×10^6 m^-1 = 5×10^6 /m 1 m = 100 cm 이므로, (5×10^6 /m) (1 m / 100 cm) = (5×10^6) (1 / 100) = 5×10^4 /cm = 5×10^4 cm^-1 답: 5×10^4 cm^-1 2024. 3. 30. 포도당 180 mg/dL를 mmol/L 단위로 환산 포도당 180 mg/dL를 mmol/L 단위로 환산 포도당 분자량 180 [참고] 환산 인자 [ https://ywpop.tistory.com/3121 ] 180 mg / (180 mg/mmol) = 1 mmol 포도당 ( 참고 https://ywpop.tistory.com/7738 ) ---> 180 mg/dL = 1 mmol/dL 1 L = 10 dL 이므로, (1 mmol/dL) (10 dL / 1 L) = 10 mmol/L [공식] Convert mg/dL to mmol/L (mg/dL) / 분자량 × 10 = mmol/L 답: 10 mmol/L [ 관련 글 https://ywpop.tistory.com/24676 ] 1 μM 포도당을 μg/mL 단위로 환산 [키워드] 농도 환산 기준 2024. 3. 28. 20 μg/kg body weight 160 lb patient 20 μg/kg body weight 160 lb patient At a dosage of 20 μg/kg body weight, how many milligrams of digitalis should a 160 lb patient receive? [참고] 환산 인자 [ https://ywpop.tistory.com/3121 ] 1 mg = 1000 μg 이므로, 20 μg × (1 mg / 1000 μg) = 0.02 mg ---> 20 μg/kg = 0.02 mg/kg 1 lb = 0.45359237 kg 이므로, 160 lb × (0.45359237 kg / 1 lb) = 72.5747792 kg (0.02 mg/kg) × 72.5747792 kg = 1.4515 mg ---> 투여량 답: 약 1... 2024. 3. 28. 0.6 μg mol/mL•min을 lb mol/ft3•day 단위로 환산 0.6 μg mol/mL•min을 lb mol/ft3•day 단위로 환산 Convert 0.6 μg mol/(mL•min) to lb mol/(ft3•day) [참고] 환산 인자 [ https://ywpop.tistory.com/3121 ] > 1 g = 10^6 μg > 1 lb = 453.59237 g > 1 L = 1000 mL > 1 m3 = 1000 L > 1 ft = 0.3048 m ---> 1 ft3 = 0.3048^3 m3 > 1 day = 24 hr > 1 hr = 60 min (0.6 μg mol/(mL•min)) (1 g / 10^6 μg) (1 lb / 453.59237 g) (1000 mL / 1 L) (1000 L / 1 m3) (0.3048^3 m3 / 1 ft3) (60 mi.. 2024. 3. 27. 0.04 g/min•m3를 lbm/hr•ft3 단위로 환산 0.04 g/min•m3를 lbm/hr•ft3 단위로 환산 [참고] 환산 인자 [ https://ywpop.tistory.com/3121 ] > 1 lb = 1 lbm = 453.59237 g ( 참고 https://ywpop.tistory.com/22440 ) > 1 hr = 60 min > 1 ft = 0.3048 m ---> 1 ft3 = 0.3048^3 m3 ( 참고 https://ywpop.tistory.com/20863 ) (0.04 g/min•m3) (1 lbm / 453.59237 g) (60 min / 1 hr) (0.3048^3 m3 / 1 ft3) = (0.04) (1 / 453.59237) (60) (0.3048^3) = 0.0001498 lbm/hr•ft3 답: 1.498×10^(.. 2024. 3. 27. 5.01 lb mass 66% copper 6.304×10^(-3) in 8.95 g/cm3 5.01 lb mass 66% copper 6.304×10^(-3) in 8.95 g/cm3 Copper can be drawn into thin wires. How many meters of 34-gauge wire (diameter = 6.304×10^(-3) in) can be produced from copper in 5.01 lbs of covellite, an ore of copper that is 66% Cu by mass? (Hint: Treat the wire as a cylinder; V of cylinder = πr^2h; d of copper = 8.95 g/cm3) (5.01 lb) (453.59237 g / 1 lb) = 2272.498 g covellite 2272.498 g .. 2024. 3. 22. 5320 gallon kerosene SST 4.02×10^9 ton density 0.965 g/cm3 5320 gallon kerosene SST 4.02×10^9 ton density 0.965 g/cm3 A supersonic aircraft consumes 5320 imperial gallons of kerosene per hour of flight and flies an average of 14 hours per day. It takes roughly seven tons of crude oil to produce one ton of kerosene. The density of kerosene is 0.965 g/cm3. How many planes would it take to consume the entire annual world production of 4.02×10^9 metric tons.. 2024. 3. 21. Ga 녹는점 29.78℃ 끓는점 2204℃ 0 G 1000 G NaCl 녹는점 801℃ Ga 녹는점 29.78℃ 끓는점 2204℃ 0 G 1000 G NaCl 녹는점 801℃ The element gallium (Ga) has the second-largest liquid range of any element, melting at 29.78 ℃ and boiling at 2204 ℃ at atmospheric pressure. a) What is the density of gallium in g/cm3 at 25 ℃ if a 1 in. cube has a mass of 0.2133 lb? b) Assume that you construct a thermometer using gallium as the fluid instead of mercury and that you define the m.. 2024. 3. 20. 이전 1 2 3 4 5 6 7 ··· 37 다음 반응형