10.01 mL grape 0.1000 M NaOH 12.44 mL tartaric acid g/L

10.01 mL grape 0.1000 M NaOH 12.44 mL tartaric acid g/L

 

 

Two 10.01 mL samples of white grape juice

were analyzed using 0.1000 M NaOH solution

by the method in this experiment.

The corrected mean titration volume of NaOH was 12.44 mL.

Calculate the tartaric acid concentration

in the white grape juice in units of g/L,

assume only tartaric acid is present in the juice.

State your answer to 2 places after the decimal point.

Do not enter units.

 

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tartaric acid는 2가산이므로,

H2A + 2NaOH → Na2A + 2H2O

 

 

 

aMV = b’M’V’

( 참고 https://ywpop.tistory.com/4689 )

 

(2) (? M) (10.01 mL) = (1) (0.1000 M) (12.44 mL)

 

? = [(1) (0.1000) (12.44)] / [(2) (10.01)]

= 0.06214 M

 

 

 

tartaric acid, H2C4H4O6의 몰질량 = 150.09 g/mol 이므로,

(0.06214 mol/L) (150.09 g/mol)

= (0.06214) (150.09)

= 9.3266 g/L

 

 

 

답: 9.33

 

 

 

 

[ 관련 예제 https://ywpop.tistory.com/19661 ] 0.230 M H2C4H4O6 35.0 mL + 0.150 M NaOH

 

[ 관련 예제 https://ywpop.tistory.com/20932 ] white wine 50.00 mL 0.03291 M NaOH 24.57 mL

 

 

 

[키워드] 타타르산 기준문서, tartaric acid 기준문서, 타타르산 적정 기준문서, tartaric acid 적정 기준문서, 타르타르산 기준문서, 타르타르산 적정 기준문서, 10.84 mL grape 0.1000 M NaOH 13.92 mL tartaric acid g/L