2C6H5COOH(s) + 15O2(g) ΔU –772.7 kJ/mol 298 K Calculate ΔH

2C6H5COOH(s) + 15O2(g) ΔU –772.7 kJ/mol 298 K Calculate ΔH

 

 

For the reaction

2 C6H5COOH(s) + 15 O2(g) → 14 CO2(g) + 6 H2O(g)

ΔU° = –772.7 kJ mol^-1 at 298 K. Calculate ΔH°.

 

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2C6H5COOH(s) + 15O2(g) → 14CO2(g) + 6H2O(g)

Δn = (14 + 6) – (15) = 5

 

 

 

ΔH = ΔU + ΔnRT

( 참고 https://ywpop.tistory.com/14717 )

 

= (–772700) + (5) (8.314) (298)

= –760312 J/mol

= –760.3 kJ/mol

 

 

 

답: –760.3 kJ/mol

 

 

 

 

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