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일반화학/[20장] 전기화학

aluminum oxide 8.00 h 1.00×10^5 A current

by 영원파란 2021. 11. 25.

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aluminum oxide 8.00 h 1.00×10^5 A current

 

 

산화알루미늄과 빙정석의 용융 혼합물에

8.00 h 동안 1.00×10^5 A의 일정한 전류가 흐를 때,

생산되는 알루미늄은 몇 kg인가?

 

 

How many kilograms of aluminum can be produced

in 8.00 h by passing a constant current of 1.00×10^5 A

through a molten mixture of aluminum oxide and cryolite?

 

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▶ 참고: 전기분해의 화학량론

[ https://ywpop.tistory.com/4461 ]

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Q = It

= (1.00×10^5 A) (8×3600 s)

= 2.88×10^9 A•s

= 2.88×10^9 C

 

 

 

Al2O3 → Al or

Al^3+ + 3e^- → Al

---> Al : e^- = 1 mol : 3 mol

 

 

 

쿨롱 → 전자 mol수 → Al mol수 → Al 질량 순으로 환산하면,

(2.88×10^9 C) (1 mol e^- / 96500 C) (1 mol Al / 3 mol e^-) (26.98 g Al / 1 mol Al)

= (2.88×10^9) (1 / 96500) (1 / 3) (26.98)

= 268402 g Al

= 268.4 kg Al

 

 

 

답: 268.4 kg

 

 

 

 

[키워드] How many kilograms of aluminum can be produced in 6.06 h by passing a constant current of 1.14×10^5 A through a molten mixture of aluminum oxide and cryolite?

 

 

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