10.00 M HNO3 125.0 mL 500.0 mL 30.00 mL NaOH 16.74 mL acid

10.00 M HNO3 125.0 mL 500.0 mL 30.00 mL NaOH 16.74 mL acid

 

 

In the titration of a solution of sodium hydroxide,

an acid titrant was prepared by diluting 125.0 mL of 10.00 mol/L nitric acid

into enough distilled water to make 500.0 mL of solution.

30.00 mL of the base was measured, and in the titration,

16.74 mL of the acid titrant was needed to neutralize.

Determine the concentration of the sodium hydroxide solution.

 

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묽힌 HNO3 용액의 몰농도를 계산하면,

MV = M’V’

진한 용액 속 용질의 몰수 = 묽은 용액 속 용질의 몰수

( 참고 https://ywpop.tistory.com/2859 )

 

(10.00 M) (125.0 mL) = (? M) (500.0 mL)

 

? = (10.00) (125.0) / (500.0) = 2.500 M

 

 

 

 

NaOH 용액의 몰농도를 계산하면,

MV = M’V’

H^+의 몰수 = OH^-의 몰수

( 참고 https://ywpop.tistory.com/4689 )

 

(2.500 M) (16.74 mL) = (? M) (30.00 mL)

 

? = (2.500) (16.74) / (30.00) = 1.395 M