72.4 g Fe 100.0℃ 10.0℃ water 100.0 g

72.4 g Fe 100.0℃ 10.0℃ water 100.0 g

 

 

100.0℃ 72.4 g 철 조각을 10.0℃ 물 100.0 g에 넣었을 때,

최종 온도 계산.

주위로 열 손실은 없다.

물의 비열 = 4.184 J/g•℃

Fe의 비열 = 0.449 J/g•℃

 

 

A coffee cup calorimeter contains 100.0 g of water at 10.0℃.

A 72.4 g sample of iron is heated to 100.0℃

and dropped into the calorimeter.

Assuming there is no heat lost to the coffee cup,

calculate the final temperature of the system.

 

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q = C m Δt

( 참고 https://ywpop.tistory.com/2897 )

 

 

 

최종 온도를 x라 두면,

 

고온 물질이 잃은 열(–q) = 저온 물질이 얻은 열(+q)

–[(0.449) (72.4) (x – 100.0)] = +[(4.184) (100.0) (x – 10.0)]

 

–32.5076x + 3250.76 = 418.4x – 4184

 

(418.4 + 32.5076)x = (3250.76 + 4184)

 

x = (3250.76 + 4184) / (418.4 + 32.5076)

= 16.5℃

 

 

 

답: 16.5℃