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PV는 일정. O2 gas 150 atm 49.0 L 1.02 atm
Oxygen gas is commonly sold in 49.0 L steel containers at a pressure of 150 atm. What volume in liters would the gas occupy at a pressure of 1.02 atm if its temperature remained unchanged?
If its temperature was raised from 20.0℃ to 35.0℃ at constant P = 150 atm?
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PV = P’V’
( 참고 https://ywpop.tistory.com/1977 )
V’ = PV / P’
= (150) (49.0) / (1.02)
= 7205.88 L
답: 7206 L
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V / T = V’ / T’
( 참고 https://ywpop.tistory.com/1978 )
V’ = VT’ / T
= (49.0) (273.15+35.0) / (273.15+20.0)
= 51.51 L
답: 51.5 L
[키워드] VT는 일정
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