0.1 M 페놀 용액의 pH

0.1 M 페놀 용액의 pH

 

 

What is the [H^+] concentration in a 0.1 M solution of phenol (C6H5OH)

if the Ka is 1.26×10^(-10)?

 

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▶ 참고: 약산의 초기농도, Ka, pH 관계식

[ https://ywpop.tistory.com/4294 ]

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x = [Ka × C]^(1/2) = [H^+]

pH = -log[H^+]

 

 

 

x = [1.26×10^(-10) × 0.1]^(1/2)

= 3.55×10^(-6) M = [H^+]

 

 

 

pH = -log[H^+]

= -log(3.55×10^(-6))

= 5.45

 

 

 

 

[참고] What is the [H^+] concentration in a 0.05 M solution of phenol (C6H5OH)

if the Ka is 1.02×10^(-10)?

 

x = [1.02×10^(-10) × 0.05]^(1/2)

= 2.26×10^(-6) M = [H^+]

 

 

 

 

[키워드] pH of 0.1 M phenol, 페놀 기준문서