균형 맞추기. BF3 + H2O → B2O3 + HF

균형 맞추기. BF3 + H2O → B2O3 + HF

BF3(g) + H2O(g) → B2O3(s) + HF(g)

 

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▶ 참고: 미정계수법 [ https://ywpop.tistory.com/3902 ]

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aBF3 + bH2O → cB2O3 + dHF

 

 

B: a = 2c ... (1)

F: 3a = d ... (2)

H: 2b = d ... (3)

O: b = 3c ... (4)

 

 

c = 1 이라 두면,

from (1), a = 2

 

from (4), b = 3

 

from (3), d = 6

 

 

답: 2BF3 + 3H2O → B2O3 + 6HF

2BF3(g) + 3H2O(g) → B2O3(s) + 6HF(g)