10^-4 M AgCl을 용해시키기 위한 NH3의 농도
10^-4 M AgCl을 용해시키기 위한 NH3의 최소 농도는?
단, AgCl의 Ksp = 10^-10, Ag(NH3)2^+의 Kf = 10^8
-----------------------------------------
AgCl(s) ⇌ Ag^+(aq) + Cl^-(aq)
Ksp = [Ag^+][Cl^-] = 10^-10
Ag^+(aq) + 2NH3(aq) ⇌ Ag(NH3)2^+(aq)
Kf = [Ag(NH3)2^+] / [Ag^+][NH3]^2 = 10^8
AgCl(s) + 2NH3(aq) ⇌ Ag(NH3)2^+(aq) + Cl^-(aq)
Keq = [Ag(NH3)2^+][Cl^-] / [NH3]^2
= Ksp × Kf
= (10^(-10)) × (10^8)
= 0.01
평형에서,
AgCl(s) + 2NH3(aq) .. ⇌ .. Ag(NH3)2^+(aq) + Cl^-(aq)
......... x-2(10^-4) ...... 10^-4 .......... 10^-4
Keq = [Ag(NH3)2^+][Cl^-] / [NH3]^2
= (10^(-4))^2 / (x - 2(10^(-4)))^2 = 0.01
((10^(-4)) / (x – 2(10^(-4))))^2 = 0.01
(10^(-4)) / (x – 2(10^(-4))) = (0.01)^(1/2) = 0.1
(10^(-4)) = 0.1x – 2×10^(-5)
x = ((10^(-4)) + 2×10^(-5)) / 0.1
= 0.0012
= 1.2×10^-3 M = [NH3]
답: 1.2×10^-3 M
[ 관련 예제 http://ywpop.tistory.com/8439 ]
'화학' 카테고리의 다른 글
How many moles of AgCl will be produced from 60.0 g of AgNO3 (0) | 2018.01.14 |
---|---|
How many moles of ZnCl2 will be produced from 23.0 g of Zn (0) | 2018.01.14 |
How many moles of Fe2O3 will be produced from 18.0 g of Fe (0) | 2018.01.14 |
How many moles of Hg will be produced from 34.0 g of HgO (0) | 2018.01.14 |
Molar solubility of AgCl in 0.0012 M NH3 (0) | 2018.01.14 |
Molar solubility of AgCl in 0.50 M NH3 (0) | 2018.01.14 |
솔레노이드 밸브. solenoid valve (0) | 2018.01.14 |
4% 소금물과 7% 소금물을 섞어서 5% 소금물 600 g (1) | 2018.01.14 |
댓글