본문 바로가기
화학

Molar solubility of AgCl in 0.0012 M NH3

by 영원파란 2018. 1. 14.

AdSense@ywpop

Molar solubility of AgCl in 0.0012 M NH3

 

 

What is the molar solubility of AgCl in 0.50 M NH3?

Ksp for AgCl is 10^-10 and the Kf for Ag(NH3)2^+ is 10^8

 

-----------------------------------------

 

AgCl(s) Ag^+(aq) + Cl^-(aq)

Ksp = [Ag^+][Cl^-] = 10^-10

 

Ag^+(aq) + 2NH3(aq) Ag(NH3)2^+(aq)

Kf = [Ag(NH3)2^+] / [Ag^+][NH3]^2 = 10^8

 

 

AgCl(s) + 2NH3(aq) Ag(NH3)2^+(aq) + Cl^-(aq)

Keq = [Ag(NH3)2^+][Cl^-] / [NH3]^2

= Ksp × Kf

= (10^(-10)) × (10^8)

= 0.01

 

 

평형에서,

AgCl(s) + 2NH3(aq) .. .. Ag(NH3)2^+(aq) + Cl^-(aq)

......... 0.0012-2x ....... x .............. x

 

 

Keq = [Ag(NH3)2^+][Cl^-] / [NH3]^2

= x^2 / (0.0012-2x)^2 = 0.01

 

(x / (0.0012-2x))^2 = 00.01

x / (0.0012-2x) = (0.01)^(1/2) = 0.1

x = 0.00012 0.2x

1.2x = 0.00012

x = 0.00012 / 1.2

= 0.0001

= 10^-4 M = [Cl^-] = [AgCl]

 

 

: 10^-4 M

 

 

[ 관련 예제 http://ywpop.tistory.com/8211 ]

 

 

반응형
그리드형(광고전용)

댓글