화학량론. 5.5 mol NaF gram MgF2

화학량론. 5.5 mol NaF gram MgF2

 

 

Mg + 2NaF → MgF2 + 2Na

If you start with 5.5 moles of sodium fluoride (NaF),

how many grams of magnesium fluoride (MgF2) will be produced?

 

 

 

NaF : MgF2 = 2 : 1 계수비(= 몰수비) 이므로,

NaF : MgF2 = 2 : 1 = 5.5 mol : ? mol

 

? = 5.5 / 2 = 2.75 mol MgF2

 

 

 

MgF2의 몰질량 = 62.30 g/mol 이므로,

2.75 mol × (62.30 g/mol) = 171.325 g MgF2

( 참고 https://ywpop.tistory.com/7738 )

 

 

 

답: 1.7×10^2 g

 

 

 

 

[키워드] Mg + 2NaF → MgF2 + 2Na 반응 기준