화합물의 몰농도와 노르말농도. 3 g BaCl2 용액 30 mL

화합물의 몰농도와 노르말농도. 3 g BaCl2 용액 30 mL

 

 

There are 3 grams of BaCl2 in 30 mL of solution.

What is the molarity of this solution?

What is the normality of this solution?

 

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MW of BaCl2 = 208.23 g/mol

Molarity = 용질 mol수 / 용액 L수

 

용질 mol수 = 3 g / (208.23 g/mol) = 0.0144 mol BaCl2

Molarity = 0.0144 mol / 0.030 L = 0.48 M BaCl2

 

Valence of BaCl2 = 2 equivalents/mol

(화합물의 당량수 = 양이온의 하전수. 따라서 Ba^2+ = 2)

0.0144 mol × (2 equivalents/mol) = 0.0288 equivalents BaCl2

 

Normality = 용질 equivalents / 용액 L수

Normality = 0.0288 equivalents / 0.030 L = 0.96 N BaCl2

  

  

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몰농도 × 당량수 = 노르말농도
0.48 M × 2 = 0.96 N

 

 

[산-염기의 노르말농도]