25.0 μL solution 26.7 μg solute concentration in ppm and mg/dL

25.0 μL solution 26.7 μg solute concentration in ppm and mg/dL

 

 

A 25.0 μL sample was found to contain 26.7 μg glucose. Express the concentration as ppm and mg/dL glucose.

 

 

25.0 μL 용액 중 용질의 질량이 26.7 μg인 용액의 농도를

ppm과 mg/dL 단위로 구하시오.

 

 

 

[참고] 환산 인자

[ https://ywpop.tistory.com/3121 ]

 

[참고] 미터법 접두어

[ https://ywpop.tistory.com/2328 ]

 

 

 

(25.0 μL) (1 L / 10^6 μL) = 2.50×10^(-5) L

 

(2.50×10^(-5) L) (10 dL / 1 L) = 2.50×10^(-4) dL

 

(26.7 μg) (1 mg / 1000 μg) = 0.0267 mg

 

 

 

1 ppm = 1 mg/L

( 참고 https://ywpop.tistory.com/5345 )

 

 

 

0.0267 mg / (2.50×10^(-5) L)

= 1068 mg/L

= 1068 ppm

= 1.07×10^3 ppm

 

 

 

0.0267 mg / (2.50×10^(-4) dL)

= 106.8 mg/dL

= 1.07×10^2 mg/dL

 

 

 

 

[키워드] 25.0 μL 26.7 μg ppm mg/dL 기준, 25.0 μL sample 26.7 μg glucose ppm mg/dL