25.00 mL KMnO4 0.2558 M C2O4^2- 20.24 mL

25.00 mL KMnO4 0.2558 M C2O4^2- 20.24 mL

 

 

What is the concentration of a KMnO4 solution

if 20.24 mL of 0.2558 M C2O4^2- solution is needed

to reduce 25.00 mL of KMnO4 solution?

2MnO4^- + 5C2O4^2- + 16H^+ → 2Mn^2+ + 10CO2 + 8H2O

 

 

 

(0.2558 mol/L) (20.24/1000 L) = 0.005177 mol C2O4^2-

( 참고 https://ywpop.tistory.com/7787 )

 

 

 

MnO4^- : C2O4^2- = 2 : 5 계수비(= 몰수비) 이므로,

MnO4^- : C2O4^2- = 2 : 5 = ? mol : 0.005177 mol

 

? = 2 × 0.005177 / 5 = 0.0020708 mol MnO4^-

 

 

 

몰농도 = 용질 mol수 / 용액 L수

= 0.0020708 mol / (25.00/1000 L) = 0.08283 M MnO4^-

 

 

 

답: 0.08283 M

 

 

 

 

[ 관련 예제 https://ywpop.tistory.com/23064 ] KMnO4 용액 20 mL + 0.05 M Na2C2O4 용액 10 mL

 

 

 

[FAQ] [①24/04/05]