완충용액의 pH. 1.00 g glycine amide 0.100 L pH
a) 1.00 g의 글라이신 아마이드 염화수소(glycine amide hydrochloride)와
1.00 g의 글라이신 아마이드(glycine amide)를
0.100 L에 녹여 만든 용액의 pH를 구하시오.
a) Find the pH of a solution prepared by dissolving
1.00 g of glycine amide hydrochloride plus
1.00 g of glycine amide in 0.100 L.
Cl-H3NCH2CONH2
Glycine amide hydrochloride (BH^+)
FW 110.54, pKa = 8.20
H2NCH2CONH2
Glycine amide (B)
FW 74.08
b) How many grams of glycine amide
should be added to 1.00 g of glycine amide hydrochloride
to give 100 mL of solution with pH 8.00?
c) What would be the pH if the solution in (a)
is mixed with 5.00 mL of 0.100 M HCl?
d) What would be the pH if the solution in (c)
is mixed with 10.00 mL of 0.100 M NaOH?
e) What would be the pH if the solution in part (a)
were mixed with 90.46 mL of 0.100 M NaOH?
(This is exactly the quantity of NaOH required
to neutralize the glycine amide hydrochloride.)
---------------------------------------------------
a) Find the pH of a solution prepared by dissolving
1.00 g of glycine amide hydrochloride plus
1.00 g of glycine amide in 0.100 L.
Henderson-Hasselbalch 식
pH = pKa + log([짝염기]/[약산])
( 참고 https://ywpop.tistory.com/1926 )
= pKa + log([B]/[BH^+])
= 8.20 + log( (1.00/74.08) / (1.00/110.54) )
= 8.37
답: pH = 8.37
[참고] n = W / M
( 참고 https://ywpop.tistory.com/7738 )
[참고] 몰농도 대신 몰수
( 참고 https://ywpop.tistory.com/13452 )
[키워드] 1.00 g glycine amide hydrochloride 1.00 g glycine amide 0.100 L pH
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