gasohol C2H6O 4.0 mol O2 mol 88 g CO2 C2H6O 125 g
Gasohol is a fuel containing ethanol (C2H6O) that burns
in oxygen (O2) to give carbon dioxide and water.
a. Write the balanced chemical equation.
b. How many moles of O2 are needed
to completely react with 4.0 moles of C2H6O?
c. If a car produces 88 g of CO2,
how many grams of O2 are used up in the reaction?
d. If you burn 125 g of C2H6O,
how many grams of CO2 and H2O can be produced?
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a. Write the balanced chemical equation.
C2H6O + 3O2 → 2CO2 + 3H2O
( 참고 https://ywpop.tistory.com/7442 )
b. How many moles of O2 are needed
to completely react with 4.0 moles of C2H6O?
C2H6O + 3O2 → 2CO2 + 3H2O
C2H6O : O2 = 1 : 3 계수비(= 몰수비) 이므로,
4.0 mol C2H6O와 반응하는 O2의 몰수를 계산하면,
C2H6O : O2 = 1 : 3 = 4.0 mol : ? mol
? = 3 × 4.0 = 12 mol O2
c. If a car produces 88 g of CO2,
how many grams of O2 are used up in the reaction?
C2H6O + 3O2 → 2CO2 + 3H2O
질량이 주어졌고, 질량을 요구했으므로,
질량비로 계산하면,
( 참고: 질량비로 계산 https://ywpop.tistory.com/5078 )
3O2 : 2CO2 = 3(32) : 2(44) = ? g : 88 g
? = 3(32) × 88 / (2(44)) = 96 g O2
d. If you burn 125 g of C2H6O,
how many grams of CO2 and H2O can be produced?
C2H6O의 몰질량 = 2(12) + 6(1) + (16) = 46 g/mol
C2H6O + 3O2 → 2CO2 + 3H2O
질량비로 계산하면,
C2H6O : 2CO2 = 46 : 2(44) = 125 g : ? g
? = 2(44) × 125 / 46 = 239 g CO2
C2H6O : 3H2O = 46 : 3(18) = 125 g : ? g
? = 3(18) × 125 / 46 = 147 g H2O
[키워드] gasohol 기준문서, gasohol dic
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