90.5 kPa 33.6 L 11.2 L work(J)

90.5 kPa 33.6 L 11.2 L work(J)

 

 

How much work (in J) is involved in a chemical reaction

if the volume decreases from 33.6 L to 11.2 L

against a constant pressure of 90.5 kPa?

 

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w = –P•ΔV

( 참고 https://ywpop.tistory.com/6336 )

 

= –(90.5 kPa) (11.2 – 33.6 L)

= –(90.5) (11.2 – 33.6)

= 2027 kPa•L

 

 

 

1 J = 1 Pa•m3 이므로,

(2027 kPa•L) (1000 Pa / 1 kPa) (1 m3 / 1000 L)

= 2027 Pa•m3

= 2027 J

 

 

 

답: 2.03×10^3 J