sucrose fructose 2.850 g 1.50 L 298.0 K 0.1843 atm osmotic

sucrose fructose 2.850 g 1.50 L 298.0 K 0.1843 atm osmotic

 

 

When a 2.850 g mixture of the sugars

sucrose (C12H22O11) and fructose (C6H12O6)

was dissolved in water to a volume of 1.50 L,

the resultant solution gave an osmotic pressure

of 0.1843 atm at 298.0 K.

What is X_sucrose of the mixture?

 

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삼투압, π = MRT

( 참고 https://ywpop.tistory.com/1921 )

 

 

 

M = π / RT

= 0.1843 / [(0.08206) (298.0)]

= 0.0075366 M

 

 

 

(0.0075366 mol/L) (1.50 L)

= 0.0113 mol

---> sugar 혼합물의 몰수

 

 

 

C12H22O11의 몰수 = x 라 두면,

C6H12O6의 몰수 = 0.0113 – x

 

 

 

> C12H22O11의 몰질량 = 342.30 g/mol

> C6H12O6의 몰질량 = 180.16 g/mol

 

 

 

몰질량(g/mol) × 몰수(mol) = 질량(g) 이므로,

( 참고 https://ywpop.tistory.com/7738 )

 

342.30x + 180.16(0.0113 – x) = 2.850

 

342.30x + 180.16(0.0113) – 180.16x = 2.850

 

162.14x = 2.850 – 180.16(0.0113)

 

x = [2.850 – 180.16(0.0113)] / 162.14

= 0.00502 mol

---> sugar 혼합물 속 C12H22O11의 몰수

 

 

 

C12H22O11의 몰분율을 계산하면,

0.00502 / 0.0113 = 0.444

( 참고 https://ywpop.tistory.com/2659 )

 

 

 

답: 0.444