molar solubility of Hg2Cl2 in pure water

molar solubility of Hg2Cl2 in pure water

 

 

Calculate the molar solubility of Hg2Cl2 in pure water.

Hg2Cl2(s) ⇌ Hg2^2+(aq) + 2Cl^-(aq) ... Ksp = 1.2×10^(-18)

 

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▶ 참고: Ksp와 몰용해도

[ https://ywpop.tistory.com/8434 ]

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Hg2Cl2(s) ⇌ Hg2^2+(aq) + 2Cl^-(aq)

( 참고 https://ywpop.tistory.com/3425 )

 

Ksp = [Hg2^2+] [Cl^-]^2

= (s) (2s)^2 = 4s^3

 

 

 

s = [Ksp / 4]^(1/3)

= [(1.2×10^(-18)) / 4]^(1/3)

= 6.7×10^(-7) M

 

 

 

답: 6.7×10^(-7) M

 

 

 

 

[참고] Hg2Cl2의 몰질량 = 472.0860 g/mol ≒ 472.09 g/mol

Convert to solubility in grams per liter

(6.7×10^(-7) mol/L) (472.09 g/mol)

= 0.0003163 g/L

= 3.2×10^(-4) g/L

 

 

 

[키워드] Hg2Cl2의 Ksp 기준문서, Hg2Cl2의 몰용해도 기준문서