26.5 L N2 22.0℃ 1.10 atm NaN3 분해. NaN3 질량

26.5 L N2 22.0℃ 1.10 atm NaN3 분해. NaN3 질량

 

 

Automobile air bags use the decomposition of sodium azide

as their source of gas for rapid inflation:

2NaN3(s) → 2Na(s) + 3N2(g)

What mass (g) of NaN3 is required

to provide 26.5 L of N2 at 22.0 °C and 1.10 atm?

 

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PV = nRT 로부터,

( 참고 https://ywpop.tistory.com/3097 )

 

n = PV / RT

= [(1.10) (26.5)] / [(0.08206) (273.15+22.0)]

= 1.20355 mol N2

 

 

 

2NaN3(s) → 2Na(s) + 3N2(g)

NaN3 : N2 = 2 : 3 계수비(= 몰수비) 이므로,

NaN3 : N2 = 2 : 3 = ? mol : 1.20355 mol

 

? = 2 × 1.20355 / 3 = 0.80237 mol NaN3

 

 

 

NaN3의 몰질량 = 65.01 g/mol 이므로,

0.80237 mol × (65.01 g/mol) = 52.16 g NaN3

( 참고 https://ywpop.tistory.com/7738 )

 

 

 

답: 52.2 g

 

 

 

 

[ 관련 예제 https://ywpop.tistory.com/17858 ] 27℃, 820.8 mmHg에서 78.0 g NaN3 분해. N2 부피

 

 

 

[키워드] NaN3 기준문서, NaN3 분해 기준문서