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일반화학/[03장] 화학량론

0.440 g H2SO3 react 0.150 M KMnO4

by 영원파란 2022. 4. 11.

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0.440 g H2SO3 react 0.150 M KMnO4

 

 

0.440 g H2SO3를 포함하는 용액과

반응하는데 필요한 0.150 M KMnO4 용액은 몇 mL인가?

 

 

How many milliliters of 0.150 M KMnO4 are required

to react with a solution that contains 0.440 g of H2SO3?

 

---------------------------------------------------

 

H2SO3의 몰질량 = 82.08 g/mol 이므로,

0.440 g / (82.08 g/mol) = 0.00536 mol H2SO3

( 참고 https://ywpop.tistory.com/7738 )

 

 

 

5H2SO3 + 2MnO4^- → 5SO4^2- + 2Mn^2+ + 4H^+ + 3H2O

 

H2SO3 : MnO4^- = 5 : 2 = 0.00536 mol : ? mol

 

? = 2 × 0.00536 / 5 = 0.002144 mol MnO4^-

 

 

 

0.002144 mol / (0.150 mol/L) = 0.0143 L

( 참고 https://ywpop.tistory.com/7787 )

 

 

 

답: 14.3 mL

 

 

 

 

[참고]

5H2SO3 + 2MnO4^- → 5SO4^2- + 2Mn^2+ + 4H^+ + 3H2O

2MnO4^- + 5H2SO3 → 2Mn^2+ + 5SO4^2- + 4H^+ + 3H2O

> MnO4^- is an oxidizing agent.

> H2SO3 is a reducing agent.

 

 

 

[키워드] redox H2SO3 + KMnO4, redox KMnO4 + H2SO3, redox H2SO3 + MnO4^-, redox MnO4^- + H2SO3

 

 

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