Ca(OH)2 용액의 pH. Ca(OH)2 1.0 g 875 mL pH pOH

Ca(OH)2 용액의 pH. Ca(OH)2 1.0 g 875 mL pH pOH

 

 

What is the pH and pOH of a solution

prepared by dissolving 1.0 g of Ca(OH)2 in water

to make 875 mL of solution?

 

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Ca(OH)2의 몰질량 = 74.09 g/mol

1.0 g / (74.09 g/mol) = 0.0135 mol Ca(OH)2

( 참고 https://ywpop.tistory.com/7738 )

 

 

 

몰농도 = 용질 mol수 / 용액 L수

= 0.0135 mol / 0.875 L = 0.0154 M

 

 

 

Ca(OH)2(aq) → Ca^2+(aq) + 2OH^-(aq)

[OH^-] = 2 × 0.0154 M = 0.0308 M

 

 

 

pOH = –log[OH^-]

= –log(0.0308) = 1.51

( 참고 https://ywpop.tistory.com/2706 )

 

 

 

[공식] Ca(OH)2 용액의 pOH

= –log[Ca(OH)2의 질량(g) / 74.09 / 용액의 부피(L) × 2]

= –log[1.0 / 74.09 / 0.875 × 2] = 1.51

 

 

 

pH = 14 – pOH

= 14 – 1.51 = 12.49

 

 

 

답: pH = 12.49, pOH = 1.51

 

 

 

 

[키워드] Ca(OH)2 용액의 pH 기준문서, Ca(OH)2 용액의 pH 사전